<span>c.She has a little homework left to finish.
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"Use the intersection of the bisectors to find the center of the circle" is the step among the choices given in the question that <span>is similar when constructing a circle inscribed in a triangle and a circle circumscribed about a triangle. The correct option among all the options that are given in the question is option "c".</span>
Answer
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For each point, start at the origin. The origin is the point with coordinates (0, 0), which is where the x- and y-axes intersect. It is just above and to the right of the number zero.
Before we start with specific points, you need to see what scale is being used. How many squares make a single unit. Starting at the origin, go to the right until you reach 1. Notice that 4 squares make 1 unit along the x-axis. Now start at the origin again and go up. Notice that again, 4 squares make 1 unit. Now we know that every 4 squares is 1 unit both in x and y. Now we start with the points.
Let's do point A together.
Start at the origin. Point A is to the left and below the origin. From the origin, move horizontally to the left until you are vertically above point A. You will have moved 6 squares left. Since the scale is 4 squares to a unit, 6 squares is one and one half units, or 1.5 units. Since you moved to the left, you are dealing with negative units. The x-coordinate of point A is -1.5. Now go down to point A. You will go exactly 4 squares to point A, so the y-coordinate of point A is -1. This gives the answer for point A.
Point A: (-1.5, -1)
Now let's skip to point E.
Start at the origin. Go right two squares to vertically above E. That is half a unit, so the x-coordinate of point E is 0.5. Now go down to point E. You go down 2 squares, so you go down 0.5 unit. Since you went down, it is negative, so the y-coordinate of point E is -0.5.
Point E: (0.5, -0.5)
Do the other points the same on your own. If you have questions, just ask in the comments.