Leah uses 2 ounces of rice to make 2/3 serving of rice. How many ounces of rice is there per serving?

Solve the system and round to the nearest hundredth. Enter the

hram777 [196]

Answer:

Step-by-step explanation:

xy = 300

x + y = 50 Solve for y

y = 50 - x substitute into xy = 300

x(50 - x) = 300 Remove the brackets.

50x - x^2 = 300 Bring the left to the right.

0 = x^2 - 50x + 300

This is a quadratic. It will have 2 solutions.

a=1

b = - 50

c = 300

Put these into the quadratic equation.

It turns out that x has two values -- both plus

x1 = 42.03

x2 = 6.97

x1 + y1 = 50

42.03 + y = 50

y = 50 - 42.03

y = 7,97

(42.03 , 7.97)

====================

x2 + y2 = 50

6.97 + y2 = 50

y2 = 50 - 6.97

y2 = 43.03

(6.97 , 43.03)

6 0

3 years ago

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Which of the following statements about the Lasso are true with respect to the OLS estimates?

mash [69]

Answer:

B and C

Step-by-step explanation:

B - The purpose of LASSO is to shrink parameter estimates towards zero, lasso shrinkage causes the estimates of the non-zero coefficients to be biased towards zero.

C- Lasso shrinks more accurately than the ridge. In the case of multiple coefficients Lasso selects only some some features and reduces the coefficients of the others to zero. This is called feature selection and it's not a possible in the ridge.

8 0

4 years ago

Bottles filled by a certain machine are supposed to contain 12 oz of liquid. In fact the fill volume is random with mean 12.01 o

Irina-Kira [14]

Answer:

a

$P(X < 12) = 0.3660$

b

$P(X < 12) = 0.1521$

Step-by-step explanation:

Considering question a

From the question we are told that

The mean is $\mu = 12.01 \ oz$

The standard deviation is $\sigma = 0.35 \ oz$

The standard error of mean is mathematically represented as

$\sigma_{x} = \frac{\sigma}{\sqrt{n} }$

=> $\sigma_{x} = \frac{0.35}{\sqrt{144} }$

=> $\sigma_{x} = 0.02917$

Generally the probability that the mean volume of a random sample of 144 bottles is less than 12 oz is mathematically represented as

$P(X < 12) = P(\frac{X - \mu }{\sigma_{x}} < \frac{12 - 12.01 }{0.02917 } )$

$\frac{X -\mu}{\sigma_{x} } = Z (The \ standardized \ value\ of \ X )$

$P(X < 12) = P(Z < -0.3425 )$

From the z table the area under the normal curve to the left corresponding to -0.3425 is

$P(X < 12) = P(Z < -0.3425 ) = 0.3660$

=> $P(X < 12) = 0.3660$

Considering question a

From the question we are told that

The mean is $\mu = 12.03 \ oz$

Generally the probability that the mean volume of a random sample of 144 bottles is less than 12 oz is mathematically represented as

$P(X < 12) = P(\frac{X - \mu }{\sigma_{x}} < \frac{12 - 12.03 }{0.02917 } )$

$P(X < 12) = P(Z < -1.0274 )$

From the z table the area under the normal curve to the left corresponding to -1.0274 is

$P(X < 12) = P(Z < -1.0274 ) =0.1521$

=> $P(X < 12) = 0.1521$

3 0

3 years ago

Perform the indicated operations; reduce the answer to the lowest terms. A. 3/10 + 6/10 b. 1/3 + 1/4 + 1/6 c. 5/6-3/6 d. 2/3-6/1

yKpoI14uk [10]

Answer:

a. 9/10

b. 3/4

c. 1/3

d. 1/15

e. 6/35

f. 1/15

g. 9/32

h. 4/15

Step-by-step explanation:

a. $\frac{3}{10}+\frac{6}{10}=\frac{9}{10}$

b. $\frac{1}{3}+\frac{1}{4}+\frac{1}{6}=\frac{4}{12}+\frac{3}{12}+\frac{2}{12}=\frac{9}{12}=\frac{3}{4}$

c. $\frac{5}{6}-\frac{3}{6}=\frac{2}{6}=\frac{1}{3}$

d. $\frac{2}{3}-\frac{6}{10}=\frac{20}{30}-\frac{18}{30}=\frac{2}{30}=\frac{1}{15}$

e. $\frac{4}{10}*\frac{3}{7}=\frac{12}{70}=\frac{6}{35}$

f. $\frac{1}{6}*\frac{6}{15}=\frac{1}{15}$

g. $\frac{1}{8}/\frac{4}{9}=\frac{1}{8}*\frac{9}{4}=\frac{9}{32}$

h. $\frac{1}{5}/\frac{3}{4}=\frac{1}{5}*\frac{4}{3}=\frac{4}{15}$

3 0

3 years ago

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Do you still have to do summer school if you fail one class? (serious question please answer, and yes i know its in math i just

photoshop1234 [79]

Answer:

In some schools yes but it depends is it a required class? if so then you'd have to retake it.

5 0

2 years ago

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