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3 years ago

Solve the system and round to the nearest hundredth. Enter the

Mathematics

2 answers:

hram777 [196]3 years ago

6 0

Answer:

Step-by-step explanation:

xy = 300

x + y = 50 Solve for y

y = 50 - x substitute into xy = 300

x(50 - x) = 300 Remove the brackets.

50x - x^2 = 300 Bring the left to the right.

0 = x^2 - 50x + 300

This is a quadratic. It will have 2 solutions.

a=1

b = - 50

c = 300

Put these into the quadratic equation.

It turns out that x has two values -- both plus

x1 = 42.03

x2 = 6.97

x1 + y1 = 50

42.03 + y = 50

y = 50 - 42.03

y = 7,97

(42.03 , 7.97)

====================

x2 + y2 = 50

6.97 + y2 = 50

y2 = 50 - 6.97

y2 = 43.03

(6.97 , 43.03)

tatuchka [14]3 years ago

4 0

Answer:

x ≈ 6.97, y ≈ 43.03; x ≈ 43.03, y ≈ 6.97

Step-by-step explanation:

System: x + y = 50, xy = 300

Alter 1st equation: y = 50 - x

Substitute: x(50 - x) = 300

Distribute: -x² + 50x = 300

Subtract: -x² + 50x - 300 = 0

Quadratic formula: x = (-50 ± √(2500 - 4 * -1 * -300))/(-2)

Simplify: x = (-50 ± √1300)/-2

Distribute: x = 25 ± (10√13)/-2

Simplify: x = 25 - 5√13 --> x ≈ 6.97, x = 25 + 5√13 --> x ≈ 43.03

Substitute: 6.97 + y = 50 --> y ≈ 43.03, 43.04 + y = 50 --> y ≈ 6.97

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The third term of an arithmetical progression is 7, and the seventh term is 2 more than 3 times the third term.Find the first te

Sphinxa [80]

General formula for n-th term of arithmetical progression is

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For 7th term we have
a(7)=a(1) +d(7-1)
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Also, we have that the <span>seventh term is 2 more than 3 times the third term,
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So we have, </span>a(7)=a(1) + 6d and a(7)=23. We can write
23=a(1) + 6d.

Now we can write a system of equations
23=a(1) + 6d
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</span>16 = 4d
d=4,

7=a(1)+2d

7=a(1)+2*4
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First term a(1)=-1, common difference d=4.

Sum of the 20 first terms is
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3 years ago

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Marysya12 [62]

Answer:

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Step-by-step explanation:

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28.20/188=.15

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