Jackson has a rope 1 foot 8 inches long. He cuts it into 4 equal pieces. How many inches long is each piece?

1 answer:

mote1985 [20]3 years ago

5 0

1 foot 8 inches.

1 foot = 12 inches.

1 foot 8 inches = 1 foot + 8 inches = 12 inches + 8 inches = 20 inches.

He cuts into 4 equal pieces.

= 20 / 4

= 5 inches.

<span>Each piece would be 5 inches long.</span>

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SHOW YOUR WORK! Marking the best response with brainliest:) thank u

sdas [7]

Step-by-step explanation:

Perimeter of a rectangle = 2l + 2w

where

l is the length

w is the width

From the question

The length is 3x + 7

The width is 2x + 2

The perimeter is

Simplify

6x + 7 + 4x + 4

Group like terms

6x + 4x + 7 + 4

We have the final answer as

Hope this helps you

6 0

3 years ago

10(a-2.5+0.56b) is this equivalent to 10a - 25+56b

kirill115 [55]

Hey there!

10(a - 2.5 + 0.56b)

= 10(a) + 10(-2.5) + 10(0.56b)

= 10a - 25 + 5.6b

= 10a + 5.6b - 25

Therefore, your answer is: 10a + 5.6b - 25

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

3 0

3 years ago

Calculate the area of triangle ABC with altitude CD, given A (6,0) B(1,5) C (2,0) and D (4,2)

Elina [12.6K]

So hmm check the picture below

the height or altitude is CD
and the base is AB

how long are those? well $\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
A&({{ 6}}\quad ,&{{ 0}})\quad 
% (c,d)
B&({{ 1}}\quad ,&{{ 5}})\\\\
C&({{ 2}}\quad ,&{{ 0}})\quad 
% (c,d)
D&({{ 4}}\quad ,&{{ 2}})
\end{array}\qquad 
% distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
AB=\sqrt{(1-6)^2+(5-0)^2}\qquad \qquad CD=\sqrt{(4-2)^2+(2-0)^2}$