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ipn [44]
3 years ago
14

I need help please , I’m so confused please

Mathematics
1 answer:
diamong [38]3 years ago
5 0

Answer:

628.32 or 628.31853071796

Step-by-step explanation:

V=πr²h or Volume equals pi r squared times h

V=pi*10²*2

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Please help (add work/reasoning if you can)
iris [78.8K]

Answer:

A

x + y >  - 9 \\  - 7 + ( - 2) >  - 9 \\  \\ 2x - 5y >  - 4 \\ 2( - 7) - 5( - 2)  \\  - 14 + 10 \\  >  - 4

5 0
3 years ago
Read 2 more answers
Please help due in 3 min
tatiyna

m(w) = 8w + 17 looks like the best answer choice for me

7 0
3 years ago
What is the inverse of the function f(x) = 2x + 1?
charle [14.2K]

Answer:

f^{-1} (x) = \frac{x-1}{2}

Step-by-step explanation:

let y = f(x) and rearrange making x the subject, that is

y = 2x + 1 ( subtract 1 from both sides )

y - 1 = 2x ( divide both sides by 2 )

\frac{y-1}{2} = x

Change y back into terms of x with x = f^{-1} (x) , so

f^{-1} (x) = \frac{x-1}{2}

4 0
4 years ago
Read 2 more answers
I need help with this ASAP!! Please and thank you..
Allushta [10]

Answer:  a) 8%

               b) 34%

               c) 12%

<u>Step-by-step explanation:</u>

a)\quad \dfrac{January\ Clothing}{January\ Payments}=\dfrac{234.75}{2800.00}=0.083\implies \large\boxed{8\%}\\\\\\b)\quad \dfrac{January\ Housing}{January\ Payments}=\dfrac{945.20}{2800.00}=0.337\implies \large\boxed{34\%}\\\\\\c)\quad \dfrac{January\ Transportation}{January\ Payments}=\dfrac{347.46}{2800.00}=0.124\implies \large\boxed{12\%}

8 0
3 years ago
Consider the following numbers 3, 6, 9, 12,...,75. Show that if we pick 15 arbitrary numbers from them, then we will find two th
garri49 [273]

Answer:

See below.

Step-by-step explanation:

There are a total of (75-3) / 3 + 1 =  25 numbers in the sequence. Now 24  of them can be paired so as to get a total of 81:

6 and 75, 9 and 72, 12 and 69............. 45 and 36, 42 + 39. That is 12 pairs with the number 3 the odd one out.

If we pick 15 random numbers there is no way we cannot pick one of these pairs which add up to 81.  For example, if we pick  12 of the first numbers in the pairs and the number 3, there are 2 numbers left to pick and these 2 would be bound to match up with  2 of the numbers of the first 12.

If we pick only 6 of the first numbers in the pairs and the 3, there are another  8 numbers left to pick so at least 2 of these are bound to match up

with some of the the first 6. If we do not pick the 3 then at least 3 will match.

Whatever combination we pick will have  1 or more pairs which add up to 81.

8 0
3 years ago
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