Answer:
The end result would be 0>-11
Step-by-step explanation:
Subtract 7 from each number and then just write it again.
7 - 7 = 0
-4 - 7 = -11
0>-11
Answer:
-0.8 is greater than -7/10
Answer:
Step-by-step explanation:
First off, you need to add up AB and BC. You would get the equation:
2(3x-4)=62, since there are two segments. Solve it/simplfy.
6x-8=62 => 6x=70 => x= 11.66666(forever)
Since you alreday solved one, you easily know the answer is c.
Answer:
-1
Step-by-step explanation:
The expression evaluates to the indeterminate form -∞/∞, so L'Hopital's rule is appropriately applied. We assume this is the common log.
d(log(x))/dx = 1/(x·ln(10))
d(log(cot(x)))/dx = 1/(cot(x)·ln(10)·(-csc²(x)) = -1/(sin(x)·cos(x)·ln(10))
Then the ratio of these derivatives is ...
lim = -sin(x)cos(x)·ln(10)/(x·ln(10)) = -sin(x)cos(x)/x
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At x=0, this has the indeterminate form 0/0, so L'Hopital's rule can be applied again.
d(-sin(x)cos(x))/dx = -cos(2x)
dx/dx = 1
so the limit is ...
lim = -cos(2x)/1
lim = -1 when evaluated at x=0.
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I find it useful to use a graphing calculator to give an estimate of the limit of an indeterminate form.