Answer:
Domain: 5, 6, 7, 8
Range: 0, -2, 10, -3
The relation is a function because each x-value has its own y-value.
Step-by-step explanation:
Domain: Set of all first elements in relation
Range: Set of all second elements in relation
How to determine if the relations is a function:
1. Identify the input values.
2. Identify the output values.
3. If each input value leads to only one output value, classify the relationship as a function.
Answer:
BC = 6
AC = square root of 72 or 8.485...
angle A = 45
Step-by-step explanation:
BC = BA
AC^2 = BA^2 + BC^2
angle A = 180-(90+45)
Answer:
My best guess would be B and C since those are the only numbers that aren't multiples of 5, and all the values of a(n) are.
The formulas:
Expand the expression:
Plug the values into the expression:
From the 64 values in the table on the left, count how many fall within the given ranges under the "classes" column in the table on the right. The "frequency" is the number of values in the data that belong to a given "class".
For example, "< -16.0" means "values below -16.0". Only one number satisfies this: -16.2 (first row, third column). So the frequency for this class is just 1.
Then for the range "-15.9 - 13.0", which probably means "numbers between 15.9 and -13.0, inclusive", the frequency is 0 because every number in the table is larger than the ones in this range.
And so on.
