The work done (in foot-pounds) in stretching the spring from its natural length to 0.7 feet beyond its natural length is 1.23 foot-pound
<h3>Data obtained from the question</h3>
From the question given above, the following data were obtained:
- Force (F) = 3 pounds
- Extension (e) = 0.6 feet
- Work done (Wd) =?
<h3>How to determine the spring constant</h3>
- Force (F) = 3 pounds
- Extension (e) = 0.6 feet
- Spring constant (K) =?
F = Ke
Divide both sides by e
K = F/ e
K = 3 / 0.6
K = 5 pound/foot
Thus, the spring constant of the spring is 5 pound/foot
<h3>How to determine the work done</h3>
- Spring constant (K) = 5 pound/foot
- Extention (e) = 0.7 feet
- Work done (Wd) =?
Wd = ½Ke²
Wd = ½ × 5 × 0.7²
Wd = 2.5 × 0.49
Wd = 1.23 foot-pound
Therefore, the work done in stretching the spring 0.7 feet is 1.23 foot-pound
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12 is 75% of what
is means equals, of means multiply
12 = 75% * what
12 = .75 * what
divide each side by .75
12/.75 = .75 * what /.75
16 = what
12 is 75 percent of 16
the answer is 16
Answer:
Is the power produced directly proportional to the wind speed.
No.
A proportional function can be described as y = a * x
So (0, 0) is on the graph, not (3, 0).
0 / 3 = 0
3800/6 = 633.33
7600/9 = 844.44
13600/12 = 1133.33
The quotient y/x should be always the same.
Answer: I think it’s the first one
Step-by-step explanation:
It says per hour and 15 bucks plus 5 bucks PERhour so you would have to be multiplying I did a question like this long ago hope you get it right
