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TiliK225 [7]
3 years ago
9

John had a roll containing 24 2/3 feet of wrapping paper. He wants to divide it into 11 pieces. First, though, he must cut off 5

/6 foot because it was torn. How long will each piece be?
Mathematics
2 answers:
tatyana61 [14]3 years ago
6 0

Given

John had a roll containing of wrapping paper  

=24\tfrac{2}{3}

First, he must cut off 5/6 foot because it was torn.

He wants to divide it into 11 pieces.

To proof

As given in question

John had a roll containing of wrapping paper

=24\tfrac{2}{3}

=\frac{74}{3}    ( solving the mixed fraction form)

 First, though, he must cut off 5/6 foot

than we get

= \frac{74}{3} - \frac{5}{6}

Taking the L.C.M of 3 and 6 is 6

=\frac{148-5}{6}

=\frac{143}{6}

=23.83 feet (approx)

He wants to divide it into 11 piece

length of the each piece

=\frac{23.83}{11}

length of the each pieces be 2.16 feet ( approx)

Hence proved




mr_godi [17]3 years ago
6 0

We are given a total size of 24 2/3 feet of wrapping paper. Convert this into fraction of denominator 6:

total paper = 24 2/3 = 74/3 = 148/6 feet

 

Subtract 5/6 foot:

remaining paper = 148/6 – 5/6 = 143/6 feet

 

Divide by 11:

<span>each piece = (143/6) ft / 11 = 143/66  ft = 2.17 ft</span>

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