12+3/(10-2*0) PLZZZZZZ ANSWERR THIS SOMEONEEE

2 answers:

7 0

Step 1: $\frac{12+3}{(10 - 2 * 0}$

Step 2: $\frac{12+3}{10}$

Step 3: The answer is 12.3

Just, do PEMDAS for future reference

rjkz [21]3 years ago

4 0

Using PEMDAS or order of operations: 2*0 is 0 and 10-0 is 10 and then 3/10 is 3/10 plus 12 is 12 3/10

You might be interested in

An accounting firm has recently recruited six graduates: three men and three women. Three of the graduates are to be selected at

solong [7]

Answer:

a) The probability tree is constructed below

b) the probability that at least two women will be selected is 0.500

Step-by-step explanation:

Given the data in the question;

a) The probability tree is as follows;

3 men, 3 women

↓

_______________________|________________________

↓ ↓ ↓ ↓

3 men 2 men 1 man 0 men

0 women 1 woman 2 woman 3 women

b) the probability that at least two women will be selected

p( at least two women would be selected) = P( there are 2 women out of 3 ) + P( there 3 women out of 3

p( at least two women would be selected) = C

³C₂ × ³C₁ / ⁶C₃ + ³C₃³C₀ / ⁶C₃

= 3!/(2!(3-2)!) × 3!/(1!(3-1)!) / 6!/(3!(6-3)!) + 3!/(3!(3-3)!) × 3!/(0!(3-0)!) / 6!/3!(6-3)!)

= 3 × 3 / 20 + 1 × 1 / 20

= 9/20 + 1/20

= 0.45 + 0.05

p( at least two women would be selected) = 0.500

Therefore, the probability that at least two women will be selected is 0.500

6 0

3 years ago

A researcher is interested in determining the mean energy consumption of a new

Nana76 [90]

Answer:

The most appropriate value of the critical value is 2.289.

Step-by-step explanation:

We are given that a researcher takes a random sample of 41 bulbs and determines that the mean consumption is 1.3 watts per hour with a standard deviation of 0.7.

We have to find that when constructing a 97% confidence interval, which would be the most appropriate value of the critical value.

Firstly, as we know that the test statistics that would be used here is t-test statistics because we don't know about the population standard deviation.

So, for finding the critical value we will look for t table at (41 - 1 = 40) degrees of freedom at the level of significance will be $\frac{1 - 0.97}{2} = 0.015$ .