Evaluate the expression for the given value of the variable y/8+12;y=32
2 answers:
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3x-2y=6
1) <span>Add -3x to both sides.
</span><span><span> 3x</span>−<span>2y</span></span>=<span>6
</span>+3x +3x
-----------------
<span>−<span>2y</span></span>=<span><span>−<span>3x</span></span>+<span>6
</span></span><span>
2) Divide both sides by -2.
</span>
= 
y=<span><span><span>32</span>x</span>−<span>3
</span></span>
3) Substitute the y with the equation
3x-2(32x-3)=6
3x-64x+6=6
4) Combine like terms
3x-64x+6=6
-61x+6=6
5) Subtract 6 from each side of the equation
-61x+6=6
-6 -6 (+6-5 gets crossed out)
--------------
-61x=0
6) Divide both sides by -61
x=0
============================================================
Now that you've got you x intercept, use the x value and substitute it into the
y=32x−3
y=32(0)-3
y=0-3
y=-3
(0,-3)
1) <span>Add -3x to both sides.
</span><span><span> 3x</span>−<span>2y</span></span>=<span>6
</span>+3x +3x
-----------------
<span>−<span>2y</span></span>=<span><span>−<span>3x</span></span>+<span>6
</span></span><span>
2) Divide both sides by -2.
</span>
y=<span><span><span>32</span>x</span>−<span>3
</span></span>
3) Substitute the y with the equation
3x-2(32x-3)=6
3x-64x+6=6
4) Combine like terms
3x-64x+6=6
-61x+6=6
5) Subtract 6 from each side of the equation
-61x+6=6
-6 -6 (+6-5 gets crossed out)
--------------
-61x=0
6) Divide both sides by -61
x=0
============================================================
Now that you've got you x intercept, use the x value and substitute it into the
y=32x−3
y=32(0)-3
y=0-3
y=-3
(0,-3)
We assume that
if xy=0
x and y=0
first make it equal to zero
minus 5 on both sides
4x^2-12x+4=0
undistribute 4 for ease
4(x^2-3x+1)=0
since 4 does not equal zero, and the only thing that will get it to zero is 0,
x^2-3x+1=0
use quadratic equation
if you hahve
ax^2+bx+c=0
x=
1x^2-3x+1=0
a=1
b=-3
c=1
x=
x=
x=
x=
or 
aprox
x=2.61803 or 0.381966
if xy=0
x and y=0
first make it equal to zero
minus 5 on both sides
4x^2-12x+4=0
undistribute 4 for ease
4(x^2-3x+1)=0
since 4 does not equal zero, and the only thing that will get it to zero is 0,
x^2-3x+1=0
use quadratic equation
if you hahve
ax^2+bx+c=0
x=
1x^2-3x+1=0
a=1
b=-3
c=1
x=
x=
x=
x=
aprox
x=2.61803 or 0.381966