A₁ = -8 This is the first term in an arithmetic sequence.
d = 3, the common difference
a(n) = a₁ + d(n-1)
a₇ = -8 + 3(7-1)
a₇ = -8 + 3(6)
a₇ = -8 + 18
a₇ = 10
To check:
a₁ = -8
a₂ = -8 + 3 = -5
a₃ = -5 + 3 = -2
a₄ = -2 + 3 = 1
a₅ = 1 + 3 = 4
a₆ = 4 + 3 = 7
a₇ = 7 + 3 = 10
Answer:#of dimes is 15 # of quarters is 10
Step-by-step explanation:method is elimination my multiplication. First equation is x+y=25 multiply it by -10. Second equation is 10x+25y=400. A quarter is .25 and a dime is .10 but to avoid all decimals I multiplied by 10 but it doesn’t matter because I did it on both sides. Use systematic equation solving to get 15y=150 then y=10. Plug it into the first to get x+10=25 subtract to get 15. Mr. Jacobs does get excessive sometimes lol.
Step-by-step explanation:
2a -5a +8a.
2a +8a -5a
10a -5a = 5a
14-7=7
<em>Answer=5a+7</em>
True/False questions = 2 points each(x).
Multiple choice questions = 3 points each(y).
She needs more than (>) 90 points.
2x + 3y > 90
