<span>The
problem wants us to find the number that the 21% is 42.
42 is the 21% of 200
How:
=> 21% = 21 /100
=> .21
In order to get the answer we need to find a number to be multiplied by .21 and
get 42 as result.
=> 50 x .21 = 10.5
=> 100 x .21 = 21
=> 150 x .21 = 31.5
=> 200 x .21 = 42
thus, 42 is the 21% of 200.</span>
Answer:
They are already in order. Just connect them.
Answer:
Step-by-step explanation:
Answer:
Step-by-step explanation:
We know that for two similar matrices
and
exists an invertible matrix
for which
[/tex]
∴ ![B^{T} = (P^{-1})^{T} A^{T} P^{T} \\](https://tex.z-dn.net/?f=B%5E%7BT%7D%20%3D%20%28P%5E%7B-1%7D%29%5E%7BT%7D%20A%5E%7BT%7D%20P%5E%7BT%7D%20%5C%5C)
Also ![P^{-1}P = I\\](https://tex.z-dn.net/?f=P%5E%7B-1%7DP%20%3D%20I%5C%5C)
and ![(P^{-1})^{T} = (P^{T})^{-1}](https://tex.z-dn.net/?f=%28P%5E%7B-1%7D%29%5E%7BT%7D%20%3D%20%28P%5E%7BT%7D%29%5E%7B-1%7D)
∴![(P^{-1})^{T}P^{T} = I](https://tex.z-dn.net/?f=%28P%5E%7B-1%7D%29%5E%7BT%7DP%5E%7BT%7D%20%3D%20I)
so, ![B^{T} = (P^{-1})^{T} A^{T} P^{T} = (P^{T})^{-1}A^{T} P^{T}\\B^{T} = A^{T} I\\B^{T} = A^{T}](https://tex.z-dn.net/?f=B%5E%7BT%7D%20%3D%20%28P%5E%7B-1%7D%29%5E%7BT%7D%20A%5E%7BT%7D%20P%5E%7BT%7D%20%3D%20%28P%5E%7BT%7D%29%5E%7B-1%7DA%5E%7BT%7D%20P%5E%7BT%7D%5C%5CB%5E%7BT%7D%20%3D%20A%5E%7BT%7D%20I%5C%5CB%5E%7BT%7D%20%3D%20A%5E%7BT%7D)
Answer:
text me the answer when you get it 832-757-5456
Step-by-step explanation: