9w+63=27
27-63= -36
-36•/•9=-4
answer: -4=w
hope this helps
Use photo math ! It’s way better than this
Answer:
The percentage of samples of 4 fish will have sample means between 3.0 and 4.0 pounds is 66.87%
Step-by-step explanation:
For a normal random variable with mean Mu = 3.2 and standard deviation sd = 0.8 there is a distribution of the sample mean (MX) for samples of size 4, given by:
Z = (MX - Mu) / sqrt (sd ^ 2 / n) = (MX - 3.2) / sqrt (0.64 / 4) = (MX - 3.2) / 0.4
For a sample mean of 3.0, Z = (3 - 3.2) / 0.4 = -0.5
For a sample mean of 3.0, Z = (4 - 3.2) / 0.4 = 2.0
P (3.2 <MX <4) = P (-0.5 < Z <2.0) = 0.6687.
The percentage of samples of 4 fish will have sample means between 3.0 and 4.0 pounds is 66.87%
