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notka56 [123]
3 years ago
14

In a dihybrid cross of two heterozygous individuals, you expect a 9:3:3:1 phenotypic ratio in the offspring, but observe a ratio

of 9:7. What is the most likely explantation?a. It is a sex-limited trait b. It is a sex-influenced trait c. Codominance d. Incomplete dominance e. Epistatic interaction of the two genes
Biology
1 answer:
almond37 [142]3 years ago
3 0

Answer:

e. Epistatic interaction of the two genes

Explanation:

The 9:7 ratio is typical of the Duplicate Recessive Epistasis.

The expected phenotypic ratiio of the offsrping of a dihybrid cross is:

9 A_B_

3 A_bb

3 aaB_

1 aabb

In the Duplicate Recessive Epistasis, the A_bb, aaB_ and aabb individuals all have the same phenotype, making for the ratio 9:7. What those three genotypes have in common is that in all of them at least one of the two genes  is homozygous recessive (either <em>aa</em> or <em>bb</em>).

This usually happens one the products of genes A and B are enzymes of the same metabolic pathway.

Whenever both A and B are present, the pathway can produce the final product and a certain phenotype. However, if any of the dominant alleles is missing, the enzyme is not produced and therefore the final product of pathway is not produced, giving the other phenotype.

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