Answer:
Three $5's and eleven $1's
Step-by-step explanation:
Answer:
0.40
Step-by-step explanation:
to find out the probability that at least one of a pair of fair dice lands of 5, given that the sum of the dice is 8
Let A = sum of dice is 8
B = one lands in 5
P(B/A) = P(AB)/P(A) by conditional probability
P(AB) = sum is 8 and one is 5
So (5,3) or (3,5)
P(A) = sum is 8.
i.e. (2,6) (2,6) (3,5) (5,3) (4,4)
Required probability
= n(AB)/n(A)
=
Answer:
-2
Step-by-step explanation:
-10 x 12 x -4 + 40 x -2 x 6 - 2
-120 x -4 - 80 x 6 - 2
480 - 480 - 2
0 - 2
-2
Answer:
8x² + 11x - 9
Step-by-step explanation:
M - N
= 5x² + 7x - 4 - 1(- 3x² - 4x + 5) ← distribute parenthesis by - 1
= 5x² + 7x - 4 + 3x² + 4x - 5 ← collect like terms
= 8x² + 11x - 9