Answer:
um what?
Step-by-step explanation:
From the trigonometry:
tan θ = (sin θ) / (cos θ)
cot θ = (cos θ) / (sin θ)
∴ tan θ + cot θ = (sin θ) / (cos θ) + (cos θ) / (sin θ)
= [ sin² θ + cos² θ]/( sin θ cos θ) = 1 /( sin θ cos θ )
note : sin² θ + cos² θ = 1
The cosine function with the given characteristics is:
f(x) = 3*cos(x/2 - pi).
<h3>
How to get the cosine function?</h3>
The general cosine function is:
f(x) = A*cos(kx + p)
Where A is the amplitude and p is the phase, then we know that:
A = 3
p = -pi
Then we have:
f(x) = 3*cos(kx - pi)
And the period is equal to 4pi, then we must have that:
k*(x + 4pi) - pi = k*x - pi + 2pi
k = 1/2
Then the function is:
f(x) = 3*cos(x/2 - pi).
If you want to learn more about cosine functions:
brainly.com/question/4372174
#SPJ4
#1 is correct!
#2 is D - ASA
Hope this helps!! :)