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ddd [48]
3 years ago
14

Can you help me in number 4

Mathematics
1 answer:
In-s [12.5K]3 years ago
5 0
The answer is J. All of them

This is because when you simplify all three expressions above, they all equal 3x+9, therefore they are all equivalent expressions.






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5-7:
garri49 [273]
The 3 panes would cost $7.65.
6 0
4 years ago
Read 2 more answers
A helicopter leaves bristol and flies due east for 10 miles.Then the helicopter flies 8miles north before landing. What is the d
DedPeter [7]

Answer:

The distance of the helicopter from the bristol is approximately 1<u>2.81 miles</u>

Step-by-step explanation:

Given:

Helicopter flies 10 miles east of bristol.

Then the helicopter flies 8 miles North before landing.

To find the direct distance between the helicopter and bristol.

Solution:

In order to find the distance of the helicopter from the bristol before landing, we will trace the path of the helicopter

The helicopter is first heading 10 miles east of bristol and then going 8 miles due north.

On tracing the path of the helicopter we find that the direct distance of the helicopter from the bristol is the hypotenuse of a right triangle formed by enclosing the path of the helicopter.

Applying Pythagorean theorem to find the hypotenuse of the triangle.

Hypotenuse^2=Short\ leg^2+Shortest\ leg^2

Hypotenuse^2=10^2+8^2

Hypotenuse^2=100+64\\Hypotenuse^2=164

Taking square root both sides.

\sqrt{Hyptenuse^2}=\sqrt{164}\\Hypotenuse = 12.81\ miles

Thus, the distance of the helicopter from the bristol is approximately 12.81 miles

6 0
4 years ago
X4y(4) = yx2(13), calculate (x+y)2
Delicious77 [7]

Please, for clarity, use " ^ " to denote exponentiation:


Correct format: x^4*y*(4) = y*x^2*(13)

This is an educated guess regarding what you meant to share. Please err on the side of using more parentheses ( ) to show which math operations are to be done first.


Your (x+y)2, better written as (x+y)^2, equals x^2 + 2xy + y^2, when expanded.

The question here is whether you can find this x^2 + 2xy + y^2 in your

"X4y(4) = yx2(13)"


Please lend a hand here. If at all possible obtain an image of the original version of this problem and share it. That's the only way to ensure that your helpers won't have to guess what the problem actually looks like.


3 0
4 years ago
The table below shows all of the possible outcomes for rolling two six sided number cubes what is the probability of rolling an
Vanyuwa [196]

<u>Answer:</u>

The probability of rolling an even number first and an odd number second is \frac{1}{4}

<u>Solution: </u>

As two cubes are 6 sided,  the total number of possibilities are (6\times6) = 36

Now in those possibilities the first number will be even and the second number will be odd.  If we check the table, such pairs are,  

(2,1), (2,3), (2,5), (4,1), (4,3), (4,5), (6,1), (6,3), (6,5)

So, we can see we have total 9 set with the combination of first number even and second number odd.  So, the probability of rolling with this combination will be \bold\frac{9}{36}=\frac{1}{4}\bold

6 0
4 years ago
Help with this please ​
andrew-mc [135]

Answer:

140

Step-by-step explanation:

this is because of alternate suplementry lines

4 0
3 years ago
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