Answer:
137 - 48 = 89, so she climbed 89
Step-by-step explanation:
Answer:
![Leg\ 1 = 8](https://tex.z-dn.net/?f=Leg%5C%201%20%3D%208)
![Leg\ 2 = 15](https://tex.z-dn.net/?f=Leg%5C%202%20%3D%2015)
Step-by-step explanation:
Given: See Attachment
Required
Determine the length of the legs
To do this, we apply Pythagoras theorem.
![Hyp^2 = Adj^2 + Opp^2](https://tex.z-dn.net/?f=Hyp%5E2%20%3D%20Adj%5E2%20%2B%20Opp%5E2)
In this case:
![17^2 = x^2 + (2x- 1)^2](https://tex.z-dn.net/?f=17%5E2%20%3D%20x%5E2%20%2B%20%282x-%201%29%5E2)
Open Bracket
![17^2 = x^2 + 4x^2- 2x-2x + 1](https://tex.z-dn.net/?f=17%5E2%20%3D%20x%5E2%20%2B%204x%5E2-%202x-2x%20%2B%201)
![17^2 = 5x^2 - 4x + 1](https://tex.z-dn.net/?f=17%5E2%20%3D%205x%5E2%20-%204x%20%2B%201)
![289= 5x^2 - 4x + 1](https://tex.z-dn.net/?f=289%3D%205x%5E2%20-%204x%20%2B%201)
Collect Like Terms
![5x^2 - 4x + 1 - 289 = 0](https://tex.z-dn.net/?f=5x%5E2%20-%204x%20%2B%201%20-%20289%20%3D%200)
![5x^2 - 4x - 288 = 0](https://tex.z-dn.net/?f=5x%5E2%20-%204x%20-%20288%20%3D%200)
Solving using quadratic formula:
![x = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B-b%5C%C2%B1%5Csqrt%7Bb%5E2%20-%204ac%7D%7D%7B2a%7D)
So:
or ![x = -7.2](https://tex.z-dn.net/?f=x%20%3D%20-7.2)
Since, x can't be negative, then:
![x = 8](https://tex.z-dn.net/?f=x%20%3D%208)
One of the leg is:
![Leg\ 1 = x](https://tex.z-dn.net/?f=Leg%5C%201%20%3D%20x)
![Leg\ 1 = 8](https://tex.z-dn.net/?f=Leg%5C%201%20%3D%208)
![Leg\ 2 = 2x - 1](https://tex.z-dn.net/?f=Leg%5C%202%20%3D%202x%20-%201)
![Leg\ 2 = 2*8 - 1](https://tex.z-dn.net/?f=Leg%5C%202%20%3D%202%2A8%20-%201)
![Leg\ 2 = 16 - 1](https://tex.z-dn.net/?f=Leg%5C%202%20%3D%2016%20-%201)
![Leg\ 2 = 15](https://tex.z-dn.net/?f=Leg%5C%202%20%3D%2015)
Answer:
An official playing field (including end zones) for the Indoor Football League has a length 29 yd longer than its width. The perimeter of the rectangular field is 158 yd. Find the length and width of the field
Step-by-step explanation:
Answer: 6.5 and 6 is the 9th term
Step-by-step explanation:
U^16 is the answer to this problem