We have the following equation:
h (t) = - 16t ^ 2 + 161t + 128
We substitute the value of h (t) = 170:
170 = -16t ^ 2 + 161t + 128
We rewrite the equation:
-16t ^ 2 + 161t + 128 - 170 = 0
-16t ^ 2 + 161t - 42 = 0
We look for the roots of the equation:
t1 = (161/32) + root (23233) / 32
t2 = (161/32) - root (23233) / 32
Answer:
The object is 170 feet off the ground at the following times:
t1 = (161/32) + root (23233) / 32
t2 = (161/32) - root (23233) / 32
Answer:
Anna spent 50 minutes reading
Step-by-step explanation:
Pete spent 180 minutes reading. Since Joey spent 45 minutes less than Pete, you can do 180-45=135. So, Joey spent 135 minutes reading. Using this, we know that Anna spent 85 minutes less than Joey. So we can do 135-85=50 minutes.
Hope this helps!
sin theta = -9/41, where theta is in Q IV; find the angle theta:
Here the opp side is -9, the hyp. is 41. The adj side is found by applying the Pyth. Thm.:
(-9)^2 + x^2 = 41^2
81 + x^2 = 1681. Then x^2 = 1600, and the adj. side (x) is +40. We know it's +40 because theta is in Q IV.
The angle theta is arcsin (-9/41). Using a calculator,
arcsin (-9/41) = -0.22 radians (which is correct because theta is in Q IV, just as -0.22 rad is in Q IV. You could express theta as a positive angle by subtracting 0.22 rad from 2pi rad: 1.78 rad. You could, of course, change these angles in radians into angles in degrees.
Answer:
8 up
Step-by-step explanation: