Just substitute the first equation into the second and solve for x: <span><span>32</span>x=−<span>12</span>x+4⟹2x=4⟹x=2</span><span>Now, since y = 3/2 * x, we have y = 3 and we are done.</span>
Okay so I am going to summarize the work out process because its a lot to
Here we go
1/3 (t) + 3/4 - 2/4 - t = ?
1/2 (simplify )
(1/3 (T)+3/4 - 1/2 - (t) = ?
t (2) / 2
1 - 2(t) / 2 = ?
3/4 (simplify this )
1/3(t)+ 3/4 - [1 - 2(t) / 2 = ?
1/3 (this is re last one you have to simplify)
L (Denominator): 3
R (Denominator): 4
L: [L.C.M] : 4
R: [L.C.M] : 3
Basically , we just switched the dominators around
So, Therefore The of t is -3/16
T = -3/16
9.
<2 and <6 are right angles by the definition of perpendicular lines.
Since corresponding angles are congruent, m || n.
11.
In a triangle, the measures of the three angles add to 180 degrees.
If one angle is a right angle, then that angle measures 90 degrees. The other two angle measures plus 90 degrees add to 180 degrees, so the other two angle measures add to 90 degrees. In a right triangle there is a right angle and two other angles that are complementary.
Now look at your problem.
One angle is a right angle.
The other two angles are complementary, so their measures add to 90 deg.
8x + 2 + 9x + 3 = 90
17x + 5 = 90
17x = 85
x = 5
Answers:
The area for the square on the left is 81m^2. This is found because all sides of this square are the same, so the length and width are the same. Just multiply 9 x 9.
The area for the triangle is 31.5m^2. We find the left side is 9 meters because the triangle shares the same side as the square on the left side. We also find the bottom side is 7 because that is the length of each side of that square because all sides on a square is the same. We then multiply 9 times 7, getting 63, we divide this by 2 because it’s a triangle.
The square on the right has the area of 225 because both length and width is 15.
Answer:
1st term= 8 2nd term=6 3rd term=4 4th term=2 5th term=0 6th term=-2 7th term=-4 8th term=-6 9th term=-8 10th term=-10
Step-by-step explanation:
hope this helps
