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Alexxandr [17]
3 years ago
6

What is the algebraic expression for the following word phrase: the quotient of 3 and z

Mathematics
2 answers:
LenKa [72]3 years ago
7 0
3/z
Or at least im quite sure, being that quotient implies division
Nataliya [291]3 years ago
6 0
3 divided by z is the answer

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Which number is not a member of the solution set of the inequality 4x ≥ 18
lapo4ka [179]

Answer:

4.4

Step-by-step explanation:

4 (4.4) ≥ 18 does not make sense. 4 x 4.4 = 17.6, which is not more than or equal to 18.

6 0
2 years ago
Read 2 more answers
A major traffic problem in the Greater Cincinnati area involves traffic attempting to cross the Ohio River from Cincinnati to Ke
yaroslaw [1]

Answer:

a. 0.563 = 56.3% probability that for the next 60 minutes (two time periods) the system will be in the delay state.

b. 0.625 = 62.5% probability that in the long run the traffic will not be in the delay state

Step-by-step explanation:

Question a:

The probability of finding a traffic delay in one period, given a delay in the preceding period, is 0.75.

The system currently is in traffic delay, so for the next time period, 0.75 probability of a traffic delay. If the next period is in a traffic delay, the following period will also have a 0.75 probability of a traffic delay. So

0.75*0.75 = 0.563

0.563 = 56.3% probability that for the next 60 minutes (two time periods) the system will be in the delay state.

b. What is the probability that in the long run the traffic will not be in the delay state? If required, round your answers to three decimal places.

If it doesn't have a delay, 85% probability of continuing without a delay.

If it has a delay, 75% probability of continuing with a delay.

So, for the long run:

x: current state

85% probability of no delay if x is in no delay, 100 - 75 = 25% if x is in delay(1-x). So

0.85x + 0.25(1 - x) = x

0.6x + 0.25 = x

0.4x = 0.25

x = \frac{0.25}{0.4}

x = 0.625

0.625 = 62.5% probability that in the long run the traffic will not be in the delay state

5 0
3 years ago
The distance between the Sun and the Earth is 1 .496 x 1O^8km and distance between the Earth and lhe Moon is 3.84 x 10^8m. Durin
Dennis_Churaev [7]

Answer:

1.49216*10^8 km

Step-by-step explanation:

The first thing is to pass all the distances to the same unit system, since the distance from the earth to the sun is in kilometers and from the earth to the moon is in meters, therefore we will pass the distance of the moon in kilometers:

3.84 x 10 ^ 8m * 1 km / 1000 m = 3.84 x 10 ^ 5 km

To calculate the distance between the moon and the sun, it would be the difference between the distance they give us in the statement, because they have a point in common which is the earth, it would be:

1.496 x 10 ^ 8 km - 3.84 x 10 ^ 5 km = 149216000 = 1.49216 * 10 ^ 8 km

Therefore the distance between the moon and the sun is 1,49216 * 10 ^ 8 km

3 0
3 years ago
The total time of minutes passes through points (0,0) and (5,6) where the x-coordinate is the total miles traveled. What is the
VikaD [51]
5 miles per 6 minutes
Divide 5 by 6 to get miles per 1 minute.
(5/6)= .83
.83 * 60 = 50 minutes
7 0
3 years ago
You are choosing between two different cell phone plans. The first plan charges a rate of 24 cents per minute. The second plan c
kupik [55]

Answer:

C_{1}(t) = 0.24*t

C_{2}(t) = 34.95 + 0.12*t

291.25 talk minutes would produce the same cost for both plans.

Step-by-step explanation:

Both plans can be modeled by a first order equation in the following format:

C(t) = C_{0} + f*t

In which C_{0} is the initial cost, f is the fee that is paid for each minute, and t is the number of minutes.

Cost of the first plan:

The problem states that the first plan charges a rate of 24 cents per minute, which means that f = 0.24.There is no initial cost, so C_{0} = 0.

The equation for this plan is:

C_{1}(t) = 0.24*t

Cost of the second plan:

The problem states that the second plan charges a monthly fee of $34.95 plus 12 cents per minute. So C_{0} = 34.95 and f = 0.12

The equation for this plan is:

C_{2}(t) = 34.95 + 0.12*t

Find the number of talk minutes that would produce the same cost for both plan:

This is the instant t in which:

C_{1}(t) = C_{2}(t)

0.24t = 34.95 + 0.12t

0.12t = 34.95

t = \frac{34.95}{0.12}

t = 291.25

291.25 talk minutes would produce the same cost for both plans.

4 0
3 years ago
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