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dolphi86 [110]
3 years ago
5

Use simultaneous equations to solve the following. Three kilograms of jam and two kilograms of butter cost $29 and six kilograms

of jam and three kilograms of butter cost $54. Find the cost of one kilogram of jam and one kilogram of butter.
Mathematics
1 answer:
artcher [175]3 years ago
6 0

Answer:

The cost of 1kg jam is $7 and the cost of 1kg butter is $4

Step-by-step explanation:

Let jam = x

butter = y

3x + 2y = 29 -----(1)

6x + 3y = 54 -----(2)

(1)×2 ->

6x + 4y = 58 -----(3)

(3)-(2) ->

y = 4

suby=4into(2)

6x + 3(4) = 54

6x = 42

x = 7

(Correct me if i am wrong)

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Bingel [31]

These are three equations and three answers.


Answers:

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  • C) x = no solutions, contradiction

Explanation:


Equation A: 20 - 4x = 12 - x + 8 - 3x

The objective is clearing the unknown, which is to isolate it in one side of the equation.

These are the steps and properties that you need to use:


1.  Combine like terms on right side:

20 - 4x  = 20 - 4x


2. Use addition property of equality (add 4x on each side).

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Conclusion: you have gotten a condition that is always true, no matter the value of x, which means that the equation has infinite solutions and it is an identity.


Equation B: 5x + 4x - 3  =  24 + 8x (note that I placed the equal sign as it was missing)


1.  Combine like terms on each side:

9x - 3 = 24 + 8x


2. Subtraction property and addition propertiy of equality (subtract 8x and add + 3 on both sides)

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Conclusion: the solution is x = 27.


Equation C: 5x + 6 = 2x + 6 + 3x - 15 (note that I placed the equal signs as it was missing)


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2. Subtraction property of equality (subtract 5x from each side)


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For your information, when the variable (x) dissapears and fhe final equality is always true (for example 0 = 0, or 20 = 20), the equation is an identity.

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