Answer:
Step-by-step explanation:
a.
The angles given are 62° and 90°.
We know sum of angles in any triangle is 180° so the third angle must be 180-90-62 = 28°
We can find the sides if we know trigonometric functions
sin28° = opp. side/ hypothenuse = CA/BA = 8/BA
BA = 8/sin 28° ≈ 17
tan62°= opp.side/adj.side= BC/AC = BC/8
BC = 8 · tan62° ≈ 15
b.
We are given 2 sides 8.5 and 6.5 and that one angle is right, so the triangle is a right triangle, therefore we can apply Pythagorean Theorem to find the third side.
6.5² +FD² = 8.5², subtract 6.5² from both sides
FD² = 8.5²- 6.5², square and combine like terms
FD² = 30, square-root both sides
FD = √30
FD ≈ 5.47722, round to the nearest tenth
FD ≈ 5.5
We can find the angles if we know trigonometric functions.
sin ∡D = FE/DE = 6.5/8.5
∡D = sin^-1 (6.5/8.5)
∡D ≈ 49.9°
cos ∡E = FE/DE = 6.5/8.5
∡E = cos^-1 (6.5/8.5)
∡E ≈ 40.1°
Answer:
1. Communative Property
2. Associative Property
3. Zero Property
Step-by-step explanation:
Answer:
1 solution: (1, 4)
Step-by-step explanation:
The two lines shown intersect ONCE, at (1, 4). This (1, 4) is the solution. There is only one solution.
Answer:
I think it is 26%
Step-by-step 124 divided by 479
(a) Yes all six trig functions exist for this point in quadrant III. The only time you'll run into problems is when either x = 0 or y = 0, due to division by zero errors. For instance, if x = 0, then tan(t) = sin(t)/cos(t) will have cos(t) = 0, as x = cos(t). you cannot have zero in the denominator. Since neither coordinate is zero, we don't have such problems.
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(b) The following functions are positive in quadrant III:
tangent, cotangent
The following functions are negative in quadrant III
cosine, sine, secant, cosecant
A short explanation is that x = cos(t) and y = sin(t). The x and y coordinates are negative in quadrant III, so both sine and cosine are negative. Their reciprocal functions secant and cosecant are negative here as well. Combining sine and cosine to get tan = sin/cos, we see that the negatives cancel which is why tangent is positive here. Cotangent is also positive for similar reasons.
