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notka56 [123]
2 years ago
8

I have 8 9 and 10 To work on I need help on Those please

Mathematics
1 answer:
hram777 [196]2 years ago
5 0
9) area= pi times radius^2
You might be interested in
(07.05 HC)
lianna [129]

Answer:

c

Step-by-step explanation:

2×8=16

not 10 that is why c is correct

8 0
3 years ago
How many real solutions does this system of equations have? xy = 9<br> y = 3x - 1
tekilochka [14]

Answer:

two real, unequal roots

Step-by-step explanation:

y is definied as y = 3x - 1.  Substitute 3x - 1 for y in xy = 9, obtaining:

x(3x - 1) = 9.  Then:

3x^2 - x - 9 = 0.  In this quadratic, the coefficients are a = 3, b = -1 and c = -9.

Calculating the discriminant b^2 - 4ac, we get (-1)^2 - 4(3)(-9), or 1 + 108, or 109.  Because the discriminant is positive, we have two real, unequal roots.

6 0
3 years ago
In ΔBCD, the measure of ∠D=90°, the measure of ∠B=31°, and CD = 1.6 feet. Find the length of BC to the nearest tenth of a foot.
son4ous [18]

Answer:

3.1066≈3.1 feet

Step-by-step explanation:

3.1066≈3.1 feet

6 0
2 years ago
Read 2 more answers
2 divided by one third
Jobisdone [24]
2 / 1/3
= 2* 3/1
= 2*3
= 6
4 0
2 years ago
Read 2 more answers
Calculate the flux of the vector field F⃗ (x,y,z)=(exy+9z+4)i⃗ +(exy+4z+9)j⃗ +(9z+exy)k⃗ through the square of side length 3 wit
ikadub [295]

The square (call it S) has one vertex at the origin (0, 0, 0) and one edge on the y-axis, which tells us another vertex is (0, 3, 0). The normal vector to the plane is \vec n=\vec\imath-\vec k, which is enough information to figure out the equation of the plane containing S:

(x\,\vec\imath+y\,\vec\jmath+z\,\vec k)\cdot(\vec\imath-\vec k)=0\implies x-z=0\implies z=x

We can parameterize this surface by

\vec s(x,y)=x\,\vec\imath+y\,\vec\jmath+x\,\vec k

for 0\le x\le\frac3{\sqrt2} and 0\le y\le3. Then the flux of \vec F, assumed to be

\vec F(x,y,z)=(e^{xy}+9z+4)\,\vec\imath+(e^{xy}+4z+9)\,\vec\jmath+(9ze^{xy})\,\vec k,

is

\displaystyle\iint_S\vec F(x,y,z)\cdot\mathrm d\vec S=\iint_S\vec F(\vec s(x,y))\cdot\vec n\,\mathrm dx\,\mathrm dy

=\displaystyle\int_0^3\int_0^{3/\sqrt2}\left((4+e^{xy}+9x)\,\vec\imath+(9+e^{xy}+4x)\,\vec\jmath+(e^{xy}+9x)\,\vec k\right)\cdot(\vec\imath-\vec k)\,\mathrm dx\,\mathrm dy

=\displaystyle\int_0^3\int_0^{3/\sqrt2}4\,\mathrm dx\,\mathrm dy=\boxed{18\sqrt2}

3 0
3 years ago
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