What is the first term of the geometric sequence whose fifth term is 1/24 and tenth term is 1/768
1 answer:
An=a1r^(n-1)
given
a5=1/24
a10=1/768
we know that
a5=1/24=a1r^(5-1) and
a10=1/768=a1r^(10-1)
so
1/24=a1r^4
1/768=a1r^9
(a1r^9)/(a1r^4)=r^5=(1/768)/(1/24)=1/32
r^5=1/32
take 5th root of both sides
r=1/2
we have
a5=a1r^4=1/24
evaluate r^4 or (1/2)^4
1/16
a1(1/16)=1/24
times both sides by 16/1
a1=16/24
a1=2/3
the first term is 2/3
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Answer:
2(3x-4)=-2(x-2)
6x-8=-2x+4
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8x=12
x=12/8
x=3/2 or x=1.5
Answer:
u = v - at
Step-by-step explanation:
v = u + at
v - at = u + at - at
v - at = u
u = v - at
Answer:
9.56
Step-by-step explanation:
4.78x2 so then your answer would be 9.56
