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Mashcka [7]
3 years ago
13

What number produces an irrational number when multiplied by 1/3

Mathematics
1 answer:
docker41 [41]3 years ago
4 0

Any irrational number will remain irrational when multiplied by a rational number.

<u>Answer: Any irrational number.</u> (Like pi or the sqr of 2.)

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Distance between two points is
Root of X2 - X1 squared + Y2 - Y1 squared
So here X2 is 0 X1 is 0 as the origin is 0,0
Root of Y2-Y1 squared is what we are left with
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Root of 1 squared
Root of 1
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Is this answer right?
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Step-by-step explanation:

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Step-by-step explanation:


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The sum of two factors of 48 is nineteen. the larger factor, x, is one more than five times the smaller factor, y. which system
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Can anyone Help I have 25 questions, 2hr 40mins remaining,
11Alexandr11 [23.1K]

Combining the like-terms, the result of the addition of polynomials f(x) and g(x) is given by:

f(x) + g(x) = 21x^3 + \frac{5}{4}x^{\frac{1}{2}} + 19x^{-\frac{1}{4}} + 8x^{-4}

<h3>How do we add polynomials?</h3>

We add polynomials combining the like-terms, that is, adding terms with the same exponent.

In this problem, the polynomials are:

  • f(x) = 3x^{\frac{1}{2}} + 7x^{-\frac{1}{4}} + 8x^{-4}
  • g(x) = -\frac{7}{4}x^{\frac{1}{2}} + 12x^{-\frac{1}{4}} - 21x^3

Combining the like terms, the addition is given by:

f(x) + g(x) = \left(3 - \frac{7}{4}\right)x^{\frac{1}{2}} + (7 + 12)x^{-\frac{1}{4}} + 8x^{-4} + 21x^3

f(x) + g(x) = 21x^3 + \frac{5}{4}x^{\frac{1}{2}} + 19x^{-\frac{1}{4}} + 8x^{-4}

More can be learned about addition of polynomials at brainly.com/question/9438778

#SPJ1

8 0
2 years ago
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