The horizontal distance between light house and boat is 1588.78 feet approximately.
The figure is given by,
Here, AB = height of the lighthouse bacon light above the water = 139 feet
Now angle ACB = 5 degree
Let the horizontal distance of light house from the boat = BC = x feet
So by trigonometric function we get,
tan 5 = AB/BC
tan 5 = 139/x
x = 139/tan 5 = 1588.78 (approximately)
Hence the horizontal distance between light house and boat is 1588.78 feet approximately.
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Answer:
it is 5/5, or if that doesn't work its 1 just in case you need to simplify
Step-by-step explanation:
from the first point, count how many squares go up, the count how many squares to the right, so up 5 over 5
Answer & Step-by-step explanation:

The diameter of the circle is 8 m and the radius of the circle is 4 units. So, now we have to plug in the numbers so we can find the circumference and the area of the circle.


So, the circumference of the circle is 25.12 m.



So, the area of the circle is 50.24 units².
Answer:
For this expression I guessed I would use subtraction because when you subtract Kimiko's miles to Celeste's miles you could see how much faster Kimiko was than Celeste.
Step-by-step explanation:
Answer:
2h 1' 1"
Step-by-step explanation:
1h = 1 hora
1' = 1 minute
1" = 1 secind
The sum of the three days is:
58' 45"
+ 40' 40"
20' 36"
= 118' 121"
118' 121" = 118' + 121"
1' = 60"
121" = 120" + 1" = (120/60) + 1 = 2' + 1"
Then:
118' + 121" = 118' + 2' ´+ 1" = 120' + 1"
1 h = 60'
(120/60) + 1 = 2h + 1'
then:
118' + 121" = 2h + 1' + 1"
= 2h 1' 1"