So lets try to prove it,
So let's consider the function f(x) = x^2.
Since f(x) is a polynomial, then it is continuous on the interval (- infinity, + infinity).
Using the Intermediate Value Theorem,
it would be enough to show that at some point a f(x) is less than 2 and at some point b f(x) is greater than 2. For example, let a = 0 and b = 3.
Therefore, f(0) = 0, which is less than 2, and f(3) = 9, which is greater than 2. Applying IVT to f(x) = x^2 on the interval [0,3}.
Learn more about Intermediate Value Theorem on:
brainly.com/question/11377865
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This is in slope-intercept form which is y=mx+b
where m is the slope and b is the intercept
in this equation -7 is m
The correct answer is -7
Answer:
Point Slope: y - 5 = 3 (x-2)
Slope Intercept : y=3x-1
Step-by-step explanation:
1.) y - 5= 3(x-2)
2.) y - 5 = 3x-6
3.) y=3x-1
99.60 or 100.00? I haven’t done this for a longgggg time
