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Serga [27]
3 years ago
10

Can someone help me

Mathematics
1 answer:
Andrei [34K]3 years ago
8 0
C hope this helps you out

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Can someone help plz!
Verizon [17]

Answer:

Do you still need this one?

Step-by-step explanation:

x\geq 1

3 0
3 years ago
Find the equation of the line passing through the points (7, 16) and (2, −4). Then state the slope and coordinates of the x- and
Elanso [62]

Answer:

Equation point-slope model is: y-16 = 4 (x-7)

Slope =4

x-intercept=(7,2)

y-intercept=(16,-4)

Step-by-step explanation:

6 0
3 years ago
A golfer hits an errant tee shot that lands in the rough. A marker in the center of the fairway is 150 yards from the center of
Gwar [14]

\bold{\huge{\underline{ Solution}}}

<h3><u>Given </u><u>:</u><u>-</u></h3>

  • A marker in the center of the fairway is 150 yards away from the centre of the green
  • While standing on the marker and facing the green, the golfer turns 100° towards his ball
  • Then he peces off 30 yards to his ball

<h3><u>To </u><u>Find </u><u>:</u><u>-</u></h3>

  • <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>distance </u><u>between </u><u>the </u><u>golf </u><u>ball </u><u>and </u><u>the </u><u>center </u><u>of </u><u>the </u><u>green </u><u>.</u>

<h3><u>Let's </u><u> </u><u>Begin </u><u>:</u><u>-</u></h3>

Let assume that the distance between the golf ball and central of green is x

<u>Here</u><u>, </u>

  • Distance between marker and centre of green is 150 yards
  • <u>That </u><u>is</u><u>, </u>Height = 150 yards
  • For facing the green , The golfer turns 100° towards his ball
  • <u>That </u><u>is</u><u>, </u>Angle = 100°
  • The golfer peces off 30 yards to his ball
  • <u>That </u><u>is</u><u>, </u>Base = 30 yards

<u>According </u><u>to </u><u>the </u><u>law </u><u>of </u><u>cosine </u><u>:</u><u>-</u>

\bold{\red{ a^{2} = b^{2} + c^{2} - 2ABcos}}{\bold{\red{\theta}}}

  • Here, a = perpendicular height
  • b = base
  • c = hypotenuse
  • cos theta = Angle of cosine

<u>So</u><u>, </u><u> </u><u>For </u><u>Hypotenuse </u><u>law </u><u>of </u><u>cosine </u><u>will </u><u>be </u><u>:</u><u>-</u>

\sf{ c^{2} = a^{2} + b^{2} - 2ABcos}{\sf{\theta}}

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

\sf{ x^{2} = (150)^{2} + (30)^{2} - 2(150)(30)cos}{\sf{100°}}

\sf{ x^{2} = 22500 + 900 - 900cos}{\sf{\times{\dfrac{5π}{9}}}}

\sf{ x^{2} = 22500 + 900 - 900( - 0.174)}

\sf{ x^{2} = 22500 + 900 + 156.6}

\sf{ x^{2} = 23556.6}

\bold{ x = 153.48\: yards }

Hence, The distance between the ball and the center of green is 153.48 or 153.5 yards

5 0
2 years ago
Alexa and Brent are each working on a 30-question assignment. Alexa completed 20% of the questions. Brent completed 30% of the q
Mandarinka [93]
So 20% of 30 is 6
30% * 30 is 9
Alexa completed 6 of 30 questions 
Brent completed 9 of 30 questions

Brent completed 3 more questions than Alexa

Hope this helps :)
6 0
3 years ago
Solve for y: 2y + 3 =11<br><br>Solve for x:<br>2/3x = 18​
laiz [17]

Answer: y=4 x=27

Step-by-step explanation: 2y+3=11

-3 -3

2y=8

/2 /2

y=4

2/3x=18

(3) (3)

2x=54

/2 /2

X=27

5 0
3 years ago
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