Ration expressions cause excluded values wherever the denominator equals zero.
So, for any expression like
-5 is an excluded value if 
For example, the simplest one would be
In fact, if you try to evaluate this function at -5, you'd have
which is undefined, and thus you can't evaluate the function, and thus -5 is an excluded value.
9514 1404 393
Answer:
3
Step-by-step explanation:
For f(x) = x^3 -2x^2 -7x +5 and x=1/(2-√3), we have ...
f(x) = ((x -2)x -7)x +5
and ...
x = 1/(2-√3) = (2+√3)/(2^2 -3) = 2+√3
Then ...
f(2+√3) = ((2 +√3 -2)(2 +√3) -7)(2 +√3) +5
= (3+2√3 -7)(2+√3) +5
= 2(√3 -2)(√3 +2) +5 = 2(3 -4) +5 = -2 +5
f(1/(2 -√3)) = 3
_____
If you really mean x = (1/2) -√3, then f(x) = (42√3 -3)/8.
Answer:
Step-by-step explanation:
0.375
Answer:
<-|---------------|----------------|--------------|->
0 1/3 2/3 1
Step-by-step explanation:
easy peasy
The answer is C) collateral
