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Naddik [55]
3 years ago
12

Maria drove to a business appointment at 50mph in the morning. Her average speed on the return trip in the afternoon was 40 mph.

The return trip took 1/4hr longer because of traffic. How far did she travel to the appointment?
Mathematics
1 answer:
MakcuM [25]3 years ago
7 0

Answer:

Distance to appointment point = 5 miles

Step-by-step explanation:

Let s be the distance to the appointment point,

We have Maria drove to a business appointment at 50mph in the morning.

Time taken in the morning

               t_m=\frac{s}{50}=0.02s

Her average speed on the return trip in the afternoon was 40 mph.

Time taken in the afternoon

               t_a=\frac{s}{40}=0.025s

Given that the return trip took 1/4hr longer because of traffic.

That is

             t_a-t_m=\frac{1}{4}hr=0.025hr

Substituting

             t_a-t_m=0.025hr\\\\0.025s-0.02s=0.025\\\\s=5miles

Distance to appointment point = 5 miles

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Answer:

\large\boxed{\sqrt{126x^{13}}=3x^6\sqrt{14x}}

Step-by-step explanation:

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Answer:

300.

Step-by-step explanation:

345 rounds down to 300.

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In the diagram above, rectangles DEFG and WXYZ are similar. The ratio of the area of DEFG to WYXZ is 1:4. A student's work to fi
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Was the 12 of GF given??
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8 0
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