We are given : Zeros x=7 and x=4 and leading coefficent 1.
In order to find the quadratic function in standard form, we need to find the factors of quadratic function first and the multiply by given leading coefficent.
For the given zeros x=7 and x=4, we get the factors (x-7) and (x-4).
So, we need to multiply (x-7) and (x-4) by foil method.
We get
(x-7)(x-4) = x*x + x* -4 -7*x -7*-4
x^2 -4x -7x +28.
Combining like terms, we get
-4x-7x = -11x
x^2 -4x -7x +28 = x^2 -11x +28.
Now, we need to multiply x^2 -11x +28 quadratic by leading coefficent 1.
We get
1(x^2 -11x +28) = x^2 -11x +28.
Therefore, the required quadratic function in standard form is x^2 -11x +28.
C = 2 * 3.14 * 4 = 25.1 to nearest tenth ( 1 decimal place)
Answer:
y = x + 5: x=y−5
2x + y = 17
: x=-1/2y+17/2
Step-by-step explanation:
I do not exactly know what you were asking but I just answered the questions, if that is not what you were looking for tell me so I can try and edit my answer
Answer:I believe 786.34
Step-by-step explanation:
You divide 180 by 73.25 which is 2.46, then multiply this number by your 320 minutes to get the answer
Answer:
(x -+2)² + (y - 4)² = 36
Step-by-step explanation:
The equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k) are the coordinates of the centre and r is the radius
Here (h, k ) = (- 2, 4) and r = 6 , then
(x - (- 2))² + (y - 4)² = 6² , that is
(x + 2)² + (y - 4)² = 36 ← equation of circle
