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lesya692 [45]
2 years ago
14

-1.8 - 6x = 6(0.1 + 3x)

Mathematics
2 answers:
Wittaler [7]2 years ago
7 0

Answer:

x = -1/10 or -0.1

Step-by-step explanation:

-1.8 - 6x = 6(0.1 + 3x)

-1.8 - 6x = 0.6 + 18x

-6x - 18x = 0.6 + 1.8

-24x = 2.4

-x = 2.4/24

-x = 24/10 / 24

-x = 24/10 * 1/24

-x = 24/240

-x = 1/10

x = -0.1

Law Incorporation [45]2 years ago
7 0

Answer:

-0.13

Step-by-step explanation:

-1.8 - 6x = 6(0.1 + 3x)

Expand the bracket

-1.8 - 6x = 6x0.1 + 6 x 2x

-1.8 -6x = 0.6 + 12x

Collect like terms

-1.8 -0.6 = 6x + 12x

-2.4 = 18x

Divide both sides by 18

-2.4/18 = 18x/18

x = -0.13

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3 years ago
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Alina measured a distance to be 2.18 miles. what is the margin of error? 2.1 miles to 2.2 miles 2.175 miles to 2.185 miles 2.185
Gre4nikov [31]

Answer:

  (b)  2.175 miles to 2.185 miles

Step-by-step explanation:

When a value is rounded, the original "exact" value is presumed to be within 1/2 of the value of one least-significant unit of the rounded number.

<h3>Application</h3>

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7 0
2 years ago
D(x)=(x^2-12x+20)/(3x)
krok68 [10]

Answers:

Vertical asymptote: x = 0

Horizontal asymptote: None

Slant asymptote: (1/3)x - 4

<u>Explanation:</u>

d(x) = \frac{x^{2}-12x+20}{3x}

      = \frac{(x-2)(x - 10)}{3x}

Discontinuities: (terms that cancel out from numerator and denominator):

Nothing cancels so there are NO discontinuities.

Vertical asymptote (denominator cannot equal zero):

3x ≠ 0  

<u>÷3</u>   <u>÷3 </u>

x ≠ 0

So asymptote is to be drawn at x = 0

Horizontal asymptote (evaluate degree of numerator and denominator):

degree of numerator (2) > degree of denominator (1)

so there is NO horizontal asymptote but slant (oblique) must be calculated.

Slant (Oblique) Asymptote (divide numerator by denominator):

  •        <u>(1/3)x - 4    </u>
  •    3x)    x² - 12x + 20
  •             <u>x²        </u>
  •                  -12x
  •                  <u>-12x         </u>
  •                             20 (stop! because there is no "x")

So, slant asymptote is to be drawn at (1/3)x - 4



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