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lesya692 [45]
3 years ago
14

-1.8 - 6x = 6(0.1 + 3x)

Mathematics
2 answers:
Wittaler [7]3 years ago
7 0

Answer:

x = -1/10 or -0.1

Step-by-step explanation:

-1.8 - 6x = 6(0.1 + 3x)

-1.8 - 6x = 0.6 + 18x

-6x - 18x = 0.6 + 1.8

-24x = 2.4

-x = 2.4/24

-x = 24/10 / 24

-x = 24/10 * 1/24

-x = 24/240

-x = 1/10

x = -0.1

Law Incorporation [45]3 years ago
7 0

Answer:

-0.13

Step-by-step explanation:

-1.8 - 6x = 6(0.1 + 3x)

Expand the bracket

-1.8 - 6x = 6x0.1 + 6 x 2x

-1.8 -6x = 0.6 + 12x

Collect like terms

-1.8 -0.6 = 6x + 12x

-2.4 = 18x

Divide both sides by 18

-2.4/18 = 18x/18

x = -0.13

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Solve for x.<br><br> x3=−1000<br><br> Enter your answer in the box.<br> x =
levacccp [35]
X³ = -1000

x = ∛-1000

x = -10

In short, Your Answer would be: -10

Hope this helps!
7 0
3 years ago
Read 2 more answers
If DB = 36 and AC = 3x - 3, what is the value of x?
algol13

Answer:

A.) 13

Step-by-step explanation:

Since DB =36, and AC is the same line, then AC = 36. The new equation is 36 = 3x - 3. Do inverse operation. Add 3 to both sides of the equation: 36+3=39 & -3+3=0. New equation is 39=3x. Finally divide. 39/3= 13.

3 0
3 years ago
Evaluate the expression below at x=5
Citrus2011 [14]
5 is the answer to the promblem


5 0
3 years ago
A football team loses 3 yards on one play and 6 yards on another play write a sum of negative intergers to represent this situat
andrew11 [14]
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7 0
3 years ago
I’m confused and don’t have an angle tool to even try to do the question
yanalaym [24]
<h3>Answer:   40</h3>

=================================================

Explanation:

JQ is longer than QN. We can see this visually, but the rule for something like this is the segment from the vertex to the centroid is longer compared to the segment that spans from the centroid to the midpoint.

See the diagram below.

The ratio of these two lengths is 2:1, meaning that JQ is twice as long compared to QN. This is one property of the segments that form when we construct the centroid (recall that the centroid is the intersection of the medians)

We know that JN = 60

Let x = JQ and y = QN

The ratio of x to y is x/y and this is 2/1

x/y = 2/1

1*x = y*2

x = 2y

Now use the segment addition postulate

JQ + QN = JN

x + y = 60

2y + y = 60

3y = 60

y = 60/3

y = 20

QN = 20

JQ = 2*y = 2*QN = 2*20 = 40

--------------

We have

JQ = 40 and QN = 20

We see that JQ is twice as larger as QN and that JQ + QN is equal to 60.

7 0
3 years ago
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