Answer:
(1, 3)
Step-by-step explanation:
You are given the h coordinate of the vertex as 1, but in order to find the k coordinate, you have to complete the square on the parabola. The first few steps are as follows. Set the parabola equal to 0 so you can solve for the vertex. Separate the x terms from the constant by moving the constant to the other side of the equals sign. The coefficient HAS to be a +1 (ours is a -2 so we have to factor it out). Let's start there. The first 2 steps result in this polynomial:
. Now we factor out the -2:
. Now we complete the square. This process is to take half the linear term, square it, and add it to both sides. Our linear term is 2x. Half of 2 is 1, and 1 squared is 1. We add 1 into the set of parenthesis. But we actually added into the parenthesis is +1(-2). The -2 out front is a multiplier and we cannot ignore it. Adding in to both sides looks like this:
. Simplifying gives us this:
On the left we have created a perfect square binomial which reflects the h coordinate of the vertex. Stating this binomial and moving the -3 over by addition and setting the polynomial equal to y:
From this form,
you can determine the coordinates of the vertex to be (1, 3)
The Answer is b. Hope that helps
Step-by-step explanation:
x²+4x=8
rearrange
x² + 4x - 8 = 0
half of 4 is 2
so
x² + 4x + 2² - 2² - 8 = 0
do x² + 4x + 2²
multiplies to give 4 adds to give 4
2+ 2
(x + 2)²
(x + 2)² - 2² - 8
(x + 2)² - 4 - 8
(x + 2)² - 12
(x + 2 + √12) (x + 2 - √12)
√12 = √4 * √3 = 2 √3
(x + 2 + 2√3) (x + 2 - 2√3)
<h3>
Answer: 31 games</h3>
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Explanation:
- 32/2 = 16 games will happen in round 1. Afterward, 16 teams are left.
- 16/2 = 8 games will happen in round 2. Afterward, 8 teams are left.
- 8/2 = 4 games happen in round 3.
- 4/2 = 2 games in round 4.
- 2/2 = 1 game as the final championship.
Count the number of times you divide by two and we have five occurrences of this. So there five rounds overall.
To get the total number of games played, we add up the quotients
16+8+4+2+1 = 31
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Or as a shortcut we can simply subtract off 1 since 1+2+4+...+2^n = 2^(n+1)-1
We can write that rule as
which is equivalent to
Answer:
11j^2k^4
Step-by-step explanation:
i think that's the answers
