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Black_prince [1.1K]
2 years ago
6

Which of the following is equivalent to 7(2x+1)-2(6x+3)=15

Mathematics
2 answers:
rodikova [14]2 years ago
8 0

Answer:

D or 2x+1

Step-by-step explanation:

first we have to distribute the 7 to the 2x+1

14x+7-2(6x+3)=15

now distribute the -2

14x+7-12x-6=15

combine like terms on the left side

2x+1=15

your answer would be D

hope this helps!

Ivenika [448]2 years ago
4 0

Answer:

2x + 1 = 15

Step-by-step explanation:

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15 less than quadruple a number w​
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4w-15

Step-by-step explanation:

For expressions that have "more than/less than" , that number goes AFTER the "whatever a number" statement because that's just how they explain it. I don't remember the exact reason why, but that is how my professor made me remember it, and yes, the order WILL affect the expression since that's a specific topic and I suppose you're being tested on how to make algebraic expressions based on descriptions.

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2 years ago
You are measuring the height of a Ferris wheel at an amusement
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Answer:

154 ft

Step-by-step explanation:

A right triangle is formed, where the height of the wheel (h) is one leg,  the distance between you and the base of the wheel is the other leg, and the distance between you and the top of the wheel is the hypotenuse (the angle included between the last two sides is 51°)

From definition:

tan(51°) = opposite/adjacent

tan(51°) = h/125

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7 0
3 years ago
Tienes un triángulo equilátero con lados de 10cm, lo divides en dos partes de manera horizontal tal que el área de ambos figuras
Tanya [424]

Answer:

x = 10/√2 ≈ 7.07

Step-by-step explanation:

Comenzaremos por dividir el triángulo en dos partes y definir H, como en la figura adjunta.

Aplicando el teorema de Tales, sabemos que:

\dfrac{l/2}{H}=\dfrac{x/2}{h}\\\\\\\dfrac{l}{H}=\dfrac{x}{h}

También sabemos que, dado que el tirángulo menor es la mitad que el triángulo mayor, la relación entre áreas es:

\dfrac{A}{A_x}=\dfrac{lH/2}{xh/2}=\dfrac{lH}{xh}=2

Dado que formamos dos triángulos rectángulos, podemos despejar el valor de H como:

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Podemos entonces despejar x de la siguiente manera:

h=\dfrac{H}{l}\cdot x=\dfrac{lH}{2x}\\\\\\2x^2\dfrac{H}{l}=lH\\\\\\2x^2=l^2\\\\\\x=\dfrac{l}{\sqrt{2}}=\dfrac{10}{\sqrt{2}}\approx7.07

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3 years ago
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