First , in order to find the answer you need to add the add the numerators which are 5 and 2 = 7 and then you need to find a common denominator.
Answer:
The interest is $883.62 and the amount is $10701.62.
Step-by-step explanation:
Find the interest =
=9818 x 0.09 x 1
=883.62.
Since P = $9818 and I = $883.62 we have,
Find the Amount=
=9818+883.62
=10701.62..
Answer:
So basically anything higher than .5 would be x>.5 so it has to be greater than or equal to .51
Step-by-step explanation:
.51 .75 .89 .56 .78 .86 .61 it goes on and on as long as it is greater than .50
Answer:
a) For the 90% confidence interval the value of 
and 
, with that value we can find the quantile required for the interval in the t distribution with df =3. And we can use the folloiwng excel code: "=T.INV(0.05,3)" and we got:
b) For the 99% confidence interval the value of 
and 
, with that value we can find the quantile required for the interval in the t distribution with df =106. And we can use the folloiwng excel code: "=T.INV(0.005,106)" and we got:
Step-by-step explanation:
Previous concepts
The t distribution (Student’s t-distribution) is a "probability distribution that is used to estimate population parameters when the sample size is small (n<30) or when the population variance is unknown".
The shape of the t distribution is determined by its degrees of freedom and when the degrees of freedom increase the t distirbution becomes a normal distribution approximately.
The degrees of freedom represent "the number of independent observations in a set of data. For example if we estimate a mean score from a single sample, the number of independent observations would be equal to the sample size minus one."
Solution to the problem
Part a
For the 90% confidence interval the value of and , with that value we can find the quantile required for the interval in the t distribution with df =3. And we can use the folloiwng excel code: "=T.INV(0.05,3)" and we got:
Part b
For the 99% confidence interval the value of and , with that value we can find the quantile required for the interval in the t distribution with df =106. And we can use the folloiwng excel code: "=T.INV(0.005,106)" and we got:
Answer:
.0417
Step-by-step explanation:
.0 is 10th's place so if we had 50 percent it would be .5
.00 is ones place so 4 percent would be .04
.0000 is where fractions come in so 3 3/4 would be .00375
