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3 years ago

Is 4/5 closer to 0 , 1 or 1/2 ?

Mathematics

1 answer:

AnnZ [28]3 years ago

6 0

Answer:

4/5 is closer to 1 then to 0 or 1/2

Step-by-step explanation:

4/5 is almost a whole number. Its more then half. And scince its more then half, we know it cant be 0. ...................................Hoped I helped! :)

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The canopy of a parachute is a semicircle with a radius of 13 feet. A company that is making parachutes for a Fourth of July cel

Alexxandr [17]

Answer:

88.5 ft sq

Step-by-step explanation:

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4 years ago

3. Evaluate the expression. If k = 3 and h = 2. (Be sure to show each step)<br> 4k+2(5k-2)-h

faltersainse [42]

Answer:

Step-by-step explanation:

Simple:

(4)(3)+2((5)(3)−2)−2

=12+2((5)(3)−2)−2

=12+2(15−2)−2

=12+(2)(13)−2

=12+26−2

=38−2

=36

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3 years ago

Helppppppppppppppppppp will hive brainliest!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Alik [6]

Answer:

the constant propertianr would be 4!

Step-by-step explanation:

1 times 4 is 4

2 times 4 is 8

3 times 4 is 12

4 times 4 is 16

4 0

3 years ago

Find the value of x this is geometry please help

trasher [3.6K]

8 because if you do the math it says 8

4 0

3 years ago

Evaluate the surface integral:S

rjkz [21]

Assuming $S$ does not include the plane $z=0$ , we can parameterize the region in spherical coordinates using

$\mathbf r(u,v)=\left\langle3\cos u\sin v,3\sin u\sin v,3\cos v\right\rangle$

where $0\le u\le2\pi$ and $0\le v\le\dfrac\pi/2$ . We then have

$x^2+y^2=9\cos^2u\sin^2v+9\sin^2u\sin^2v=9\sin^2v$
$(x^2+y^2)=9\sin^2v(3\cos v)=27\sin^2v\cos v$

Then the surface integral is equivalent to

$\displaystyle\iint_S(x^2+y^2)z\,\mathrm dS=27\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\pi/2}\sin^2v\cos v\left\|\frac{\partial\mathbf r(u,v)}{\partial u}\times \frac{\partial\mathbf r(u,v)}{\partial u}\right\|\,\mathrm dv\,\mathrm du$

We have

$\dfrac{\partial\mathbf r(u,v)}{\partial u}=\langle-3\sin u\sin v,3\cos u\sin v,0\rangle$
$\dfrac{\partial\mathbf r(u,v)}{\partial v}=\langle3\cos u\cos v,3\sin u\cos v,-3\sin v\rangle$
$\implies\dfrac{\partial\mathbf r(u,v)}{\partial u}\times\dfrac{\partial\mathbf r(u,v)}{\partial v}=\langle-9\cos u\sin^2v,-9\sin u\sin^2v,-9\cos v\sin v\rangle$
$\implies\left\|\dfrac{\partial\mathbf r(u,v)}{\partial u}\times\dfrac{\partial\mathbf r(u,v)}{\partial v}\|=9\sin v$

So the surface integral is equivalent to

$\displaystyle243\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv\,\mathrm du$
$=\displaystyle486\pi\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv$
$=\displaystyle486\pi\int_{w=0}^{w=1}w^3\,\mathrm dw$

where $w=\sin v\implies\mathrm dw=\cos v\,\mathrm dv$ .

$=\dfrac{243}2\pi w^4\bigg|_{w=0}^{w=1}$
$=\dfrac{243}2\pi$

4 0

3 years ago