<span>6b^3 (2a+7b)
</span>
<span><span>(<span>6b^3</span>)</span><span>(<span>2a+7b</span><span>)
</span></span></span>
<span><span><span>=(<span>6b^3</span>)</span><span>(2a)</span></span>+<span><span>(<span>6b^3</span>)</span><span>(7b)
</span></span></span>
<span><span>=12ab^3</span>+<span>42<span>b^4]
Answer: </span></span></span>
<span><span><span>12a</span><span>b^3</span></span>+<span>42<span>b^4</span></span></span>
7.1(6)+4.8(6)= 71.4 the answer is $71.4
Answer:
x = 0.3, y = 5.3, z = 17.3
Step-by-step explanation:
Since given question is incomplete, so here is the complete table for the distance from the mean.
Temp (°F) 29 38 45 31 50 58 62
Distance from the mean 15.7 6.7 x 13.7 y 13.3 z
It's given that the mean of the data is 44.7
Since distance from the mean of a data is the absolute value of the difference of data and mean,
Therefore, distance from the mean of the data will be,
x = |44.7 - 45| = 0.3 (absolute value of the difference)
y = |44.7 - 50| = 5.3
z = |44.7 - 62| = 17.3
Answer:
four n squared divided by 7
Step-by-step explanation:
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