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Harlamova29_29 [7]
4 years ago
8

Two cards are drawn without replacement from a standard deck of 52 playing cards. What is the probability of choosing a red card

for the second card drawn, if the first card, drawn without replacement, was a diamond? Express your answer as a fraction or a decimal number rounded to four decimal places.
Mathematics
1 answer:
joja [24]4 years ago
7 0

Answer: \dfrac{3}{51}

Step-by-step explanation:

Given : The total number of cards in a deck = 52

Number of red cards = 26

There are two types of red  cards : diamond and heart.

Number of diamond cards = 13

The probability that the first card is a diamond :-

\dfrac{13}{52}=\dfrac{1}{4}

Since diamond is also a red card.

Now, the total cards left = 51

The number of red cards left = 12

The probability that the second card is a red card (without repetition) is given by :-

\dfrac{12}{51}

Now, the probability of choosing a red card for the second card drawn, if the first card, drawn without replacement, was a diamond :-

\dfrac{1}{4}\times\dfrac{12}{51}=\dfrac{3}{51}

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6 0
3 years ago
In a two-digit number, the units digit is 5 more than the tens digit. The number is 6 less than 4 times the sum of the digits. F
KonstantinChe [14]

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Step-by-step explanation:

Let the 2 digit number = xy

y = x + 5 - - - (1)

10x + y = 4(x + y) - 6

10x + x + 5 = 4(x + x + 5) - 6

11x + 5 = 4(2x + 5) - 6

11x + 5 = 8x + 20 - 6

11x + 5 = 8x + 14

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From (1)

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8 0
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two points are: (1, 3), and (3, 7)

Calculate:
(x1, y1) = (1, 3) and (x2, y2) = (3, 7)
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Answer :  y = 2x + 1




Hope that helps!!!


8 0
3 years ago
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