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enyata [817]
3 years ago
10

One zero of x3 – 3x2 – 6x + 8 = 0 is -2. What are the other zeros of the function?

Mathematics
1 answer:
hram777 [196]3 years ago
7 0
Consider this solution, if it is possible, check the result:
1) if to divide polynomial 'x³-3x²-6x+8' on 'x+2' result is: x²-5x+4, then x³-3x²-6x+8=(x+2)(x²-5x+4);
2) x²-5x+4=(x-1)(x-4), then
3) x³-3x²-6x+8=(x+2)(x-1)(x-4).
4) zeros are: -2;1;4. Other zeros are: 1 and 4.
Answer: 1;4.
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