A quadrilateral has 4 vertices and the sum of the measures of the interior angles is 360 degrees. There cannot be 4 diagonals in a quadrilateral.
Answer:
(7x-5)(3x+4)
Step-by-step explanation:
Answer:
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FOR BOB!!!!!!!
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░░░▌░▄▄▄▐▌▀▀▀░░ Dis is Bob
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░░░░░░░▀███▀█░▄░░ Help Bob
░░░░░░▐▌▀▄▀▄▀▐▄░░ take over
░░░░░░▐▀░░░░░░▐▌░░ brainly.
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Copy and paste to help Bob.
We can do it together!#TEAM BOB
FOR BOB!!!!!!!
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░░░█▀▄▄▄█░▀▀░░
░░░▌░▄▄▄▐▌▀▀▀░░ Dis is Bob
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▀█▌░░░▄░▀█▀░▀ ░░
░░░░░░░▄▄▐▌▄▄░░░
░░░░░░░▀███▀█░▄░░ Help Bob
░░░░░░▐▌▀▄▀▄▀▐▄░░ take over
░░░░░░▐▀░░░░░░▐▌░░ brainly.
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Copy and paste to help Bob.
We can do it together!
Step-by-step explanation:
Answer:
-17y+16x
Step-by-step explanation:
-3(3y -2x) +2(5x-4y)
Distribute
-9y +6x +10x -8y
Combine like terms
-9y -8y+ 6x+10x
-17y+16x
Refer to the photo. Use Pythagorean theorem of a^2 + b^2 = c^2
