1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ValentinkaMS [17]
3 years ago
5

What is the volume of the square pyramid with base edges 4 m and height 3 m?

Mathematics
1 answer:
kicyunya [14]3 years ago
8 0

Answer:

Volume of the pyramid = 16m³ or 16 cubic meters.

Step-by-step explanation:

The equation for the volume of a pyramid is:

V=\frac{b*h}{3}

where b = area of base and h = height.

In this case, the base is a square with a side length of 4m.

Area of the square base = (4m)² = b = 16m²

h = 3m

Insert b and a into the volume of a pyramid equation.

V=\frac{3m*16m}{3}

= 16m³

Volume of the pyramid = 16m³ or 16 cubic meters.

You might be interested in
Jesse has two packages of 36TACKS and 16 TACKS. How many garage sale posters can she put up if she uses 4TACKS for each poster?
hodyreva [135]

Answer: 21 posters or 13 posters, please read the explanation since your wording was confusing.


Step-by-step explanation: Okay if you have two packs of 36 and 16 which is 104, you divide by 4 tacks. You end up getting 21 posters.


If you mean there are only 36 and 16 you get 52 and divide by 4. You end up having 13 posters.


7 0
4 years ago
2root3 sin^<a href="/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="ac9eec">[email&#160;protected]</a> - <a href
Phantasy [73]

Answer:

Step-by-step explanation:

2\sqrt{3} sin^{2} \alpha -cos\alpha =0\\2\sqrt{3} (1-cos ^2 \alpha )-cos \alpha =0\\2\sqrt{3} -2\sqrt{3} cos^2 \alpha -cos \alpha =0\\2\sqrt{3} cos^2 \alpha +cos \alpha -2\sqrt{3} =0\\cos \alpha =\frac{-1 \pm\sqrt{1^2-4*2\sqrt{3}*(-2\sqrt{3})  } }{2*2\sqrt{3} } \\=\frac{-1 \pm\sqrt{1+48} }{4\sqrt{3} } \\=\frac{-1\pm7}{4\sqrt{3} } \\either~cos \alpha =\frac{6}{4\sqrt{3} }=\frac{\sqrt{3} }{2} \\=cos \frac{\pi }{6} ,cos(2\pi -\frac{\pi }{6} )\\=cos \frac{\pi}{6} ,cos \frac{11\pi }{6}

\alpha =2 n\pi+ \frac{\pi }{6} ,2n\pi +\frac{11\pi }{6} (general~solution)

or~cos\alpha =-\frac{7}{4\sqrt{3} } \\ \alpha =cos^{-1}( \frac{-7}{4\sqrt{3} } )

5 0
3 years ago
PLEASE HELP!! SIMPLE QUESTION!!
alexira [117]
The answer is, -7.4. :) Originally how it came out to be was -7.416198487. So as long as you're rounding up, since the one is below five then the 4 shall remain the same. 



Hope I helped out! Good luck
8 0
3 years ago
Read 2 more answers
Jada and Lin are comparing inches and feet. Jada says that the constant of proportionality is 12. Lin says it is 1/2. Do you agr
Pavel [41]

Answer:

i agree with jada

Step-by-step explanation:

i agree with jada because 12 inches are in 1 foot so you need 12 constantly to compare inches and feet

5 0
4 years ago
Explain why this algorithm works. In particular, Alice uses the numbers a = 3589 and 15619 as exponents. How are they related? S
Paraphin [41]

Answer:

The following attached is the solution. Hope it helps.

4 0
3 years ago
Other questions:
  • The quotient of 25 and the sum of 3 and a number that equals 28 is what?
    9·1 answer
  • 5. What is the value of this function evaluated at F(-3)?<br> F(x)=2x² + 5x - 9
    9·1 answer
  • The functions f(x)=−3/4x+2 1/4 and g(x)=(1/2)^x+1 are shown in the graph.
    15·1 answer
  • The graph of a quadratic function has a minimum at (0, 2). The graph contains the point (-3, 11). What is another point on the g
    11·2 answers
  • D. None of the above<br> If you get this right I will mark you as a brainliest
    8·1 answer
  • Solve -1 4/5 x= 9. <br> A) 5 <br> B) 1/5 <br> C) -5 <br> D) -1/5
    15·1 answer
  • A local movie theater is increasing ticket pricesby 10%. If a student ticket originally cost $8.50,how much will the theater be
    14·2 answers
  • HELPP!!!!!!!!!!!!!!!!!.
    8·1 answer
  • What is 4,567 grams, in kilograms? (1 kg= 1,000 grams.)
    11·1 answer
  • Solve the following:
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!