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Snezhnost [94]
3 years ago
14

Mary gets an annual salary of $56,780. if she is paid semimonthly, what is the amount of her semimonthly gross pay?

Mathematics
2 answers:
WITCHER [35]3 years ago
5 0

The answer is 2,365.83

Ulleksa [173]3 years ago
3 0
 <span>There are 52 weeks in a year. Being paid biweekly means being paid every other week, or 26 times a year. 

$567.20 * 26 

There are 12 months in a year. If Mary is paid semimonthly, she is paid twice a month, or 24 times a year. 

$56,780 / 24</span>
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If tanA+sinA=m and tanA-sinA=n.prove that m^2-n^2=4√mn
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Let a=\tan A and b=\sin A. Then

m^2-n^2=(a+b)^2-(a-b)^2=(a^2+2ab+b^2)-(a^2-2ab+b^2)=4ab

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and

mn=(a+b)(a-b)=a^2-b^2

\implies4\sqrt{mn}=4\sqrt{\tan^2A-\sin^2A}

The expression under the square root can be rewritten as

\tan^2A-\sin^2A=\dfrac{\sin^2A}{\cos^2A}-\sin^2A=\sin^2A\left(\dfrac1{\cos^2A}-1\right)=\sin^2A(\sec^2A-1)

Recall that

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\tan^2A-\sin^2A=\sin^2A\tan^2A

and assuming \sin A>0 and \tan A>0, we end up with

4\sqrt{\tan^2A-\sin^2A}=4\tan A\sin A

so that

m^2-n^2=4\sqrt{mn}

as required.

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