I'm kinda guessing but I think it's 4.5 square feet because each triangle has 108 inches of area when you multiply by 6 you get 648 then from there you turn that into square feet
3o'clock - directly to the right of the origin; on the x axis - (5,0)
6o'clock - directly below the origin; on the y-axis - (0,-5)
9o'clock - directly to the left of the origin; on the x-axis, (-5,0)
12o'clock - directly above the origin; on the y-axis, - (5,0)
Answer:
y = 7x - 5
Step-by-step explanation:
y=mx+b Where m is the slope and b is the y-intercept
The computation shows that the placw on the hill where the cannonball land is 3.75m.
<h3>How to illustrate the information?</h3>
To find where on the hill the cannonball lands
So 0.15x = 2 + 0.12x - 0.002x²
Taking the LHS expression to the right and rearranging we have:
-0.002x² + 0.12x -.0.15x + 2 = 0.
So we have -0.002x²- 0.03x + 2 = 0
I'll multiply through by -1 so we have
0.002x² + 0.03x -2 = 0.
This is a quadratic equation with two solutions x1 = 25 and x2 = -40 since x cannot be negative x = 25.
The second solution y = 0.15 * 25 = 3.75
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Complete question:
The flight of a cannonball toward a hill is described by the parabola y = 2 + 0.12x - 0.002x 2 . the hill slopes upward along a path given by y = 0.15x. where on the hill does the cannonball land?
