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BlackZzzverrR [31]
3 years ago
6

Find the area of this quarter circle. r=6

Mathematics
1 answer:
boyakko [2]3 years ago
5 0

28.3

Step-by-step explanation:

imagine it's a complete circle, and find its are

pi × r^2

which is 36pi (keep ur answer in pi for now)

because it's a quarter of a circle ( 1/4) we decide the are of the full circle by 4 to get the quarter's area

36pi ÷4 = 28.27433388 which is about 28.3 ( as u see we kept it in pi for a more accurate number)

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If 2x-10=4, what must x squelch to?
mr_godi [17]

Answer:

x=7

Step-by-step explanation:

2x-10=4 add 10 to both sides

2x=14 divide both sides by 2

x=7

3 0
2 years ago
Determine ſ(2) where f(x) =x+1/4x-2
umka2103 [35]
F(X)= x+1/4x-2
f(2) = (2 + 1)/[(4)(2) - 2]
f(2) = 3/6 = 1/2
6 0
2 years ago
What number is needed to complete the pattern below? 5 10 3 15 20 13 25 30 __?
djverab [1.8K]
23
because
the pattern is
(5 10) ..1.. (15 20) ..2.. (25 30) ..3..


..1... = 3
..2.. = 13
so ..3.. = 23
4 0
2 years ago
Read 2 more answers
A store randomly samples 603 shoppers over the course of a year and finds that 142 of them made their visit because of a coupon
fiasKO [112]

Answer:

The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

A store randomly samples 603 shoppers over the course of a year and finds that 142 of them made their visit because of a coupon they'd received in the mail.

This means that n = 603, \pi = \frac{142}{603} = 0.2355

95% confidence level

So \alpha = 0.05, z is the value of Z that has a p-value of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 - 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2016

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 + 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2694

The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).

8 0
2 years ago
Which ratio is equivalent to 1 to 8?<br> 7 to 14<br> 7 to 9<br> 6 to 41<br> 6 to 48
Ivan

6 to 48 simplified

it becomes 1 to 8

so the answer is 6 to 48

plz mark as brainliest

5 0
2 years ago
Read 2 more answers
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