P=1886/25 or 75 11/25
Hope this helps :)
Answer:
hmax = 628 ft
Step-by-step explanation:
The bullet will reach its maximum height when its velocity h'(t) becomes zero. The equation of motion is
h(t) = -16t^2 + 200t + 3
Taking the derivative of h(t) is
h'(t) = -32t + 200
Solving for t when h'(t) = 0, we get
t = 200/32 = 6.25 s
and this is the time it takes for the bullet to reach its maximum height. Using this value for t into h(t), we get
h = -16(6.25 s)^2 + 200(6.25 s) + 3
= 628 ft
Answer: Third option is correct
Step-by-step explanation: The y-intercepts match the constants (b in y=mx+b format) The y-values shaded above the line y≥2x+4 are correct. The y-values shaded in the region below the y≤2x -2 are also correct.
Maybe this...?
3(3) + 2(8)
Yes it can, <span>The reduced form of </span><span>1624/2000</span><span> is </span><span>203/<span>250</span></span>
