The answer is B. You do a slide timing so the slide will change when it hits the time you put it on. I hope I helped. I'm pretty sure that's the right answer. If it isn't, I'm sorry.
Answer:
Part a : Weight of chocolate in vat is 31130.17 lbf
Part b : Pressure at the bottom of tank is 4.29 psig
Part c : The body will float as its density is less than that of chocolate.
Explanation:
Part a
Weight of chocolate in the vat is given as
![W=m \times g\\W= \rho V \times g](https://tex.z-dn.net/?f=W%3Dm%20%5Ctimes%20g%5C%5CW%3D%20%5Crho%20V%20%5Ctimes%20%20g)
Here
- W is the weight of the chocolate which is to be calculated
- ρ is the density of chocolate which is calculated from following formula
![\rho=S \times \rho_{w}](https://tex.z-dn.net/?f=%5Crho%3DS%20%5Ctimes%20%5Crho_%7Bw%7D)
Here
S is the specific gravity which is given as 1.24
is the density of water which is 62.43 ![lb_m/ft^3](https://tex.z-dn.net/?f=lb_m%2Fft%5E3)
So density is
![\rho=S \times \rho_{w}\\\rho=1.24 \times 62.43\\\rho=77.41 lb_m/ft^3](https://tex.z-dn.net/?f=%5Crho%3DS%20%5Ctimes%20%5Crho_%7Bw%7D%5C%5C%5Crho%3D1.24%20%5Ctimes%2062.43%5C%5C%5Crho%3D77.41%20lb_m%2Fft%5E3)
- V is the volume of the vat calculated from the diameter and height as below
![V=\pi d^2 h/4](https://tex.z-dn.net/?f=V%3D%5Cpi%20d%5E2%20h%2F4)
Here
d is the diameter of the vat which is 4 ft.
h is the height of the vat which is 8 ft.
![V=\frac{\pi d^2 h}{4}\\V=\frac{\pi 8^2\times 8}{4}\\V=402.13 ft^3](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B%5Cpi%20d%5E2%20h%7D%7B4%7D%5C%5CV%3D%5Cfrac%7B%5Cpi%208%5E2%5Ctimes%20%208%7D%7B4%7D%5C%5CV%3D402.13%20ft%5E3)
- Here the value of g is 32.17
. This is used to convert
to ![lb_f](https://tex.z-dn.net/?f=lb_f)
Substituting values in equation of Weight gives
![W= \rho V \times g\\W= 77.41\, \frac{lb_m}{ft^3} \times 402.13 \, ft^3 \times 32.17 \frac{ft}{s^2} \\W=31130.17 \ \, 32.17 \frac{lb_m ft}{s^2}\\W=31130.17\,lb_f](https://tex.z-dn.net/?f=W%3D%20%5Crho%20V%20%5Ctimes%20%20g%5C%5CW%3D%2077.41%5C%2C%20%5Cfrac%7Blb_m%7D%7Bft%5E3%7D%20%5Ctimes%20402.13%20%5C%2C%20ft%5E3%20%5Ctimes%20%2032.17%20%20%5Cfrac%7Bft%7D%7Bs%5E2%7D%20%5C%5CW%3D31130.17%20%5C%20%20%20%5C%2C%2032.17%20%5Cfrac%7Blb_m%20ft%7D%7Bs%5E2%7D%5C%5CW%3D31130.17%5C%2Clb_f)
So the weight of chocolate in the vat is 31130.17 lbf
Part b
Pressure is given as
![P=\frac{W}{A}](https://tex.z-dn.net/?f=P%3D%5Cfrac%7BW%7D%7BA%7D)
Here
- W is the weight calculated above
- A is the area which is calculated as below
![A=\pi r^2\\A=50.26 ft^2](https://tex.z-dn.net/?f=A%3D%5Cpi%20r%5E2%5C%5CA%3D50.26%20ft%5E2)
Now pressure is given as
![P=\frac{31130.17}{50.26}\\P=619.315 \, lb_f/ft^2\\P=\frac{619.315}{144} lb_f/in^2\\P=4.29 psig](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B31130.17%7D%7B50.26%7D%5C%5CP%3D619.315%20%5C%2C%20%20lb_f%2Fft%5E2%5C%5CP%3D%5Cfrac%7B619.315%7D%7B144%7D%20lb_f%2Fin%5E2%5C%5CP%3D4.29%20psig)
So the Pressure is 4.29 psig
Part c
As the average density of human body is given 61.49
which is less than that of chocolate so the body will float in the vat.
The two possible reasons of worker's death can be
- Broken ribs/neck resulting in failure of vital organs.
- Inhalation of Chocolate and Fillings of Lungs with the Chocolate
- Resistance of the mixer blades.
lst = ["Star Wars", "Movie 2", "Movie 3", "Movie 4"]
print(lst[0])
I wrote my code in python 3.8. Best of luck
Answer:
n = 9
Explanation:
To find the answer we need to check at what point the running time of algorithm A is equal the running time of B:
1000*n*n = n*n*n*n*n
1000 = n*n*n = n^3
n = ∛(1000) = 10 (when n equals ten A equal B)
For any integer greater than ten B > A and for any integer smaller than ten B < A. The greatest integer for which B < A is nine, therefore nine is our answer.
A B
1000n^2 n^5
n = 8 64000 < 32768
n = 9 81000 < 59049
n = 10 100000 = 100000
n = 11 121000 > 161051
n = 12 144000 > 248832