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Answer:
Because of the newly developed biometric technology, the FBI was able to
quickly identify two suspects.
The blurry photos released by the FBI after the bombing prompted
researchers to improve their early biometric software.
Because biometric technology was unavailable at the time, the Boston
Marathon bomber remains at large.
The Boston Marathon bombing made researchers aware of how biometric
technology is sometimes useless and ineffective.
Explanation:
Based on the scenario above about the leading-trailing system Both technician A and B are incorrect.
<h3>How many brake shoes function?</h3>
There are known to be two shoes function that are said to be working a way where both become either the trailing shoe or leading shoe based on whether the vehicle is moving forward or backward.
Therefore we can say that, Based on the scenario above about the leading-trailing system Both technician A and B are incorrect.
Learn more about trailing system from
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Answer:
The correct answer is C. Sometimes.
Explanation:
A database index is a structure that aims to speed up selections and selective operations on a database. An index reduces the number of comparisons required to find one or more database records. This avoids having to perform a so-called full table scan, whereby all records in the table have to be run through sequentially.
Therefore, if the search does not focus correctly on the necessary data, this search will not always determine the index of the goal. Therefore, the user must correctly handle the search keywords to collaborate with the system.
Answer:
Check the explanation
Explanation:
#!usr/bin/python
#FileName: sieve_once_again.py
#Python Version: 2.6.2
#Author: Rahul Raj
#Sat May 15 11:41:21 2010 IST
fi=0 #flag index for scaling with big numbers..
n=input('Prime Number(>2) Upto:')
s=range(3,n,2)
def next_non_zero():
"To find the first non zero element of the list s"
global fi,s
while True:
if s[fi]:return s[fi]
fi+=1
def sieve():
primelist=[2]
limit=(s[-1]-3)/2
largest=s[-1]
while True:
m=next_non_zero()
fi=s.index(m)
if m**2>largest:
primelist+=[prime for prime in s if prime] #appending rest of the non zero numbers
break
ind=(m*(m-1)/2)+s.index(m)
primelist.append(m)
while ind<=limit:
s[ind]=0
ind+=m
s[s.index(m)]=0
#print primelist
print 'Number of Primes upto %d: %d'%(n,len(primelist))
if __name__=='__main__':
sieve()
