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3 years ago

I need help with my math

Mathematics

1 answer:

belka [17]3 years ago

3 0

Ok it is 494784 so hope it helps

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Jen uses 8.6 gallons of gasoline to drive 164.7 miles. Which is the best estimate for thenumber of miles per gallon of gasoline

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Answer:

Step-by-step explanation:

164.7/8.6 = 19.15

about 20 miles per gallon

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3 years ago

Jane mixes 3 gallons of red paint (r) for every 6 gallons of blue paint (b). Write one equations that show the relationship betw

RUDIKE [14]

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Step-by-step explanation:

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2 years ago

If you was born five years ago how old would u be

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3 years ago

Read 2 more answers

Can someone please help me real quick?

Ivahew [28]

Answer:

Big square - unshaded = shaded

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Step-by-step explanation:

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1 year ago

a student takes two subjects A and B. Know that the probability of passing subjects A and B is 0.8 and 0.7 respectively. If you

aniked [119]

Answer:

0.64 = 64% probability that the student passes both subjects.

0.86 = 86% probability that the student passes at least one of the two subjects

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Passing subject A

Event B: Passing subject B

The probability of passing subject A is 0.8.

This means that $P(A) = 0.8$

If you have passed subject A, the probability of passing subject B is 0.8.

This means that $P(B|A) = 0.8$

Find the probability that the student passes both subjects?

This is $P(A \cap B)$ . So

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

$P(A \cap B) = P(B|A)P(A) = 0.8*0.8 = 0.64$

0.64 = 64% probability that the student passes both subjects.

Find the probability that the student passes at least one of the two subjects

This is:

$p = P(A) + P(B) - P(A \cap B)$

Considering $P(B) = 0.7$ , we have that:

$p = P(A) + P(B) - P(A \cap B) = 0.8 + 0.7 - 0.64 = 0.86$

0.86 = 86% probability that the student passes at least one of the two subjects

3 0

3 years ago