A= q over 5c+3
Hope this helps
what is range of the inverse of the relation {(1, 7), (-2, 4), (5, 6), (2, 8)} A. {1, 2,5} B. {-4, 6, 7, 8} C. {1, 5} D. {-4, 7,
Rufina [12.5K]
The answer should be the domain of this relation. {-2, 1, 2, 5} but I do not see that as one of your answer choices.
The inverse of a relation is when you switch the domain and range. In other words, the domain of the original relation becomes the range of the inverse.
You know this is just a formula, right?
(y+5)^2 + (x-1)^2 = 16
[^2 meaning squared]
Answer:
see explanation
Step-by-step explanation:
let y = f(x) and rearrange making x the subject, that is
y = 
x + 4 ( multiply through by 2 to clear the fraction )
2y = x + 8 ( subtract 8 from both sides )
2y - 8 = x
Change y back into terms of x with x = 
(x) , then
(x ) = 2x - 8
(4) = 2(4) - 8 = 8 - 8 = 0
